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erica [24]
3 years ago
10

HELP ASAP PLEASE!!

Mathematics
1 answer:
DaniilM [7]3 years ago
5 0
The initial number of beads is:
 m
 After making a necklace for her mom, the number of pearls is:
 m-18
 For each bracelet, the number of pearls is:
 N = (total amount of beads) / (number of bracelets)
 Substituting values:
 N = (m-18) / k
 Answer:
 
she used to make each bracelet about:
 
N = (m-18) / k beads
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Garrett buys tickets to a concert. He pays $24.50 for each ticket plus a
Kay [80]

24.50 x 8.50 = 33.0

131 ÷ 33 = 3.9696969697

8 0
3 years ago
If bc is the diameter of the circle below, what is the area of the circle
dangina [55]

Answer:

option a.

radius of the circle=3 units.

area of the circle= pi×r²

area of circle=pi×3²

area of circle=pi×9units²

5 0
3 years ago
Read 2 more answers
If n is a positive integer, how many 5-tuples of integers from 1 through n can be formed in which the elements of the 5-tuple ar
sleet_krkn [62]

This question is incomplete, the complete question is;

If n is a positive integer, how many 5-tuples of integers from 1 through n can be formed in which the elements of the 5-tuple are written in increasing order but are not necessarily distinct.

In other words, how many 5-tuples of integers  ( h, i , j , m ), are there with  n ≥ h ≥ i ≥ j ≥ k ≥ m ≥ 1 ?

Answer:

the number of 5-tuples of integers from 1 through n that can be formed is [ n( n+1 ) ( n+2 ) ( n+3 ) ( n+4 ) ] / 120

Step-by-step explanation:

Given the data in the question;

Any quintuple ( h, i , j , m ), with n ≥ h ≥ i ≥ j ≥ k ≥ m ≥ 1

this can be represented as a string of ( n-1 ) vertical bars and 5 crosses.

So the positions of the crosses will indicate which 5 integers from 1 to n are indicated in the n-tuple'

Hence, the number of such quintuple is the same as the number of strings of ( n-1 ) vertical bars and 5 crosses such as;

\left[\begin{array}{ccccc}5&+&n&-&1\\&&5\\\end{array}\right] = \left[\begin{array}{ccc}n&+&4\\&5&\\\end{array}\right]

= [( n + 4 )! ] / [ 5!( n + 4 - 5 )! ]

= [( n + 4 )!] / [ 5!( n-1 )! ]

= [ n( n+1 ) ( n+2 ) ( n+3 ) ( n+4 ) ] / 120

Therefore, the number of 5-tuples of integers from 1 through n that can be formed is [ n( n+1 ) ( n+2 ) ( n+3 ) ( n+4 ) ] / 120

4 0
3 years ago
Consider the table of the powers of 8.
garri49 [273]
C loser that’s the correct number
8 0
2 years ago
HELPP PLEASE ASAP Use the Pythagorean theorem to find the missing length in the right triangle
qwelly [4]

Answer:

c = 10

Step-by-step explanation:

The pythagoras theorem :

a² + b² = c²

a = 6 and b = 8

6² + 8² = c²

36+64 = c²

100 = c²

c = √100

c= 10

Hope this helped and brainliest please

3 0
2 years ago
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