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3 years ago

My sister needs help lol. (She is young)

Mathematics

1 answer:

scZoUnD [109]3 years ago

4 0

Answer:

The answer is A-2

Step-by-step explanation:

because half of 4 (Which is the width of the flower garden) is 2 (Which would be the width of the Vegetable garden.

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How much does he/she pay with 10 %

ss7ja [257]

Answer:

5085

Step-by-step explanation:

price after discount is 5000- 10% of 5000 = 4500

V.A.T = 13% of 4500 = (13/100)*4500= 13*45= 585

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3 years ago

What is f(x)=2x^2+5 multiply by g(x)=2x

Kryger [21]

Answer:

4x^3 +10x

Step-by-step explanation:

for f(x) × g(x) you should multiply their functions :

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3 years ago

✨6 Grade Math✨ PLEASE HELP I RLLY DONT GET IT

ratelena [41]

Answer:

a. 12s + 19j - 3

36 + 28 - 3 = 61

Shirt (per unit cost):

Before Discount: $12

After Discount: $12 - $3 = $9

Jeans (pair cost):

Before Discount: $19

After Discount: $19 - $3 = $16

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8 0

3 years ago

Find the equation of the line perpendicular to y = 3x + 6 and containing the point (-9,-5).

neonofarm [45]

The equation of the line perpendicular to y = 3x + 6 and containing the point (-9,-5) is $y = \frac{-1}{3}x - 8$

Solution:

Given that line perpendicular to y = 3x + 6 and containing the point (-9, -5)

We have to find the equation of line

The slope intercept form is given as:

y = mx + c ------ eqn 1

Where "m" is the slope of line and "c" is the y - intercept

Let us first find the slope of line

The given equation of line is y = 3x + 6

On comparing the given equation of line y = 3x + 6 with eqn 1, we get,

m = 3

Thus the slope of given equation of line is 3

We know that product of slopes of given line and slope of line perpendicular to given line is equal to -1

Slope of given line $\times$ slope of line perpendicular to given line = -1

$3 \times \text{ slope of line perpendicular to given line }= -1$

$\text{ slope of line perpendicular to given line } = \frac{-1}{3}$

Let us now find the equation of line with slope $m = \frac{-1}{3}$ and containing the point (-9, -5)

Substitute $m = \frac{-1}{3}$ and (x, y) = (-9, -5) in eqn 1

$-5 = \frac{-1}{3}(-9) + c\\\\-5 = 3 + c\\\\c = -8$

Thus the required equation of line is:

Substitute $m = \frac{-1}{3}$ and c = -8 in eqn 1

$y = \frac{-1}{3}x - 8$

Thus the required equation of line perpendicular to given line is found

6 0

3 years ago