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Darina [25.2K]
2 years ago
14

Given f(x)= -2x -13, what is f(-3) -7?A: -26B: -14C: -7D: 0E: 26

Mathematics
1 answer:
DochEvi [55]2 years ago
4 0

Answer:

B: -14

Step-by-step explanation:

given that f(x) = -2x - 13,

we can find the value of f(-3) by simply plugging in -3 for x

f(-3) = -2(-3) - 13

f(-3) = -7

Because we are dealing with the expression f(-3) - 7, we still have one more step. Let's plug in -7 for f(-3)

- 7 - 7 = -14

Therefore, f(-3) - 7 will give us B: -14

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Formulate the situation as a system of two linear equations in two variables. Be sure to state clearly the meaning of your x- an
slega [8]

Answer:

1) There were 33 $4,000 investors and 27 $8,000 investors.

2) The solution in x = 4, y = 9.

3) There were 24 nickels and 56 dimes.

Step-by-step explanation:

1) A lawyer has found 60 investors for a limited partnership to purchase an inner-city apartment building, with each contributing either $4,000 or $8,000. If the partnership raised $348,000, then how many investors contributed $4,000 and how many contributed $8,000?

I am going to say that:

x is the number of investors that contributed 4,000.

y is the number of investors that contributed 8,000.

Building the system:

There are 60 investors. So:

x + y = 60

In all, the partnership raised $348,000. So:

4000x + 8000y = 348000

I am going to simplify by 4000. So:

x + 2y = 87

Solving the system:

The elimination method is a method in which we can transform the system such that one variable can be canceled by addition. So:

1)x + y = 60

2)x + 2y = 87

I am going to multiply 1) by -1. So we have

1)-x - y = -60

2)x + 2y = 87

By addition, the x are going to cancel each other

-x + x - y + 2y = -60 + 87

y = 27

For x:

x + y = 60

x = 60-y = 60-27 = 33

There were 33 $4,000 investors and 27 $8,000 investors.

2) Solve the system by row-reducing the corresponding augmented matrix.

2x + y = 17

x + y = 13

This system has the following augmented matrix:

\left[\begin{array}{ccc}2&1&17\\1&1&13\end{array}\right]

To help the row reducing, i am going to swap the first with the second line:

L1  L2

So we have:

\left[\begin{array}{ccc}1&1&13\\2&1&17\end{array}\right]

Now, reducing the first column.

L2 = L2 - 2L1

So we have:

\left[\begin{array}{ccc}1&1&13\\0&-1&-9\end{array}\right]

Now we do:

L2 = -L2

And the matrix is:

\left[\begin{array}{ccc}1&1&13\\0&1&9\end{array}\right]

Now to reduce the second column, we do:

L1 = L1 - L2

\left[\begin{array}{ccc}1&0&4\\0&1&9\end{array}\right].

So the solution is:

x = 4, y = 9.

3) A jar contains 80 nickels and dimes worth $6.80. How many of each kind of coin are in the jar?

I am going to say that x is the number of nickels and y is the number of dimes.

Each nickel is worth 5 cents and each dime is worth 10 cents.

Building the system:

There are 80 coins in all:

x + y = 80

They are worth $6.80. So:

0.05x + 0.10y = 6.80

Solving the system:

1)x + y = 80

2)0.05x + 0.10y = 6.80

I am going to divide 1) by -10, so we can cancel y. So:

1)-0.10x - 0.10y = -8

2)0.05x + 0.10y = 6.80

Adding:

-0.10x + 0.05x - 0.10y + 0.10y = -8 + 6.80

-0.05x = -1.2 *(-100)

5x = 120

x = \frac{120}{5}

x = 24

Also

x + y = 80

y = 80-x = 80-24 = 56

There were 24 nickels and 56 dimes.

8 0
3 years ago
Rename as a mixed number in simplest form. 15 22/20
Semenov [28]
16 1/10
Because you have 15 and then for 22/20 it is a improper fraction so take 20 away from it to get 2/10 then add 1 to 15 for 16 and then simplify 2/20 to 1/10
8 0
2 years ago
Read 2 more answers
a shipment of sugar fills 4 1/3 containers. if each container holds 2 1/7 tons of sugar, what is the amount of sugar in the enti
emmasim [6.3K]

To find the answer we need multiply the number of containers by number tons of sugar each container has.

(4 1/3 )*(2 1/7).

To calculate , we need to convert mixed numbers into improper fractions.

4 1/3 = (4*3 +1)/3 = 13/3

2 1/7 = (2*7+1)/7 =15/7

(4 1/3 )*(2 1/7) = (13/3) * (15/7) = (13*5)/7 = 65/7 = 9 2/7 (tons)

Answer: 9 2/7 tons.


8 0
2 years ago
12dogs to 92 cats whats the ratio as a fraction in simplest form
DedPeter [7]

12 dogs to 92 cats.

12/92

Both 12 and 92 are divisible by 4.

12/4=3

92/4=23

Simplified ratio: 3/23

There are 3 dogs for every 23 cats.

4 0
3 years ago
Solve the proportion. <br> x/4 = 2/5<br> x = ?
max2010maxim [7]
Multiply 4 on both sides.

x = 8 / 5

x = 1 3/5

Hope this helps!
8 0
2 years ago
Read 2 more answers
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