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3 years ago

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Given f(x)= -2x -13, what is f(-3) -7?A: -26B: -14C: -7D: 0E: 26

1 answer:

DochEvi [55]3 years ago

4 0

Answer:

B: -14

Step-by-step explanation:

given that f(x) = -2x - 13,

we can find the value of f(-3) by simply plugging in -3 for x

f(-3) = -2(-3) - 13

f(-3) = -7

Because we are dealing with the expression f(-3) - 7, we still have one more step. Let's plug in -7 for f(-3)

- 7 - 7 = -14

Therefore, f(-3) - 7 will give us B: -14

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HELP MEEEEEEEEEEEEEEEEEEEEE PLEASE!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

kap26 [50]

<u>Part a</u>

Setting $x=6$ , $y=7.9(1.02)^6 \approx \boxed{8.9}$

<u>Part b</u>

Setting $x=14$ , $y=7.9(1.02)^{14} \approx \boxed{10.4}$

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1 year ago

vfiekz [6]

Answer:

21 Students

Step-by-step explanation:

140 x .15 = 21

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3 years ago

Write each missing number 7+2=2+

Firdavs [7]

7+2=2+6 because 7+2=8 and 2+6 is = to 8 as well

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3 years ago

Read 2 more answers

X^4-28x^2=0 solve algebraically

Paha777 [63]

$x^4 - 28x^2 = 0$

$x^2(x^2 - 28) = 0$

$x^2 = 0 \ \ or \ \ (x^2 - 28) = 0$

$x = 0 \ \ or \ \ x^2 = 28$

$x = 0 \ \ or \ \ x = \pm \sqrt{28}$

$x = 0 \ \ or \ \ x = \pm2 \sqrt{7}$

---------------------------------------------------
Answer : x = 0 or 2√7 or -2√7
---------------------------------------------------

8 0

3 years ago

The explicit rule for the arithmetic sequence shown in the graph is a↓n=9.5+2(n-1)

Virty [35]

Answer:

True.

Step-by-step explanation:

The explicit form for an arithmetic sequence is:

$a_n=a_1+d(n-1)$

where $a_1$ is the first term and $d$ is the common difference.

The common difference here is 2 because the y's are going up by 2 while the x's are going up by 1.

Yes, the common difference is the slope.

So we have d=2.

The first term is 9.5 because that is what happens when x=1.

x is n.

y is $a_n$ .

So the answer is true.

----

You can also verify by plugging in numbers for n and see if you get the outputs mentioned in the pairs given:

Let n=1:

$a_1=9.5+2(1-1)$

$a_1=9.5+2(0)$

$a_1=9.5+0$

$a_1=9.5$

Let n=2:

$a_2=9.5+2(2-1)$

$a_2=9.5+2(1)$

$a_2=9.5+2$

$a_2=11.5$

Let n=3:

$a_3=9.5+2(3-1)$

$a_3=9.5+2(2)$

$a_3=9.5+4$

$a_3=13.5$

Let n=4:

$a_4=9.5+2(4-1)$

$a_4=9.5+2(3)$

$a_4=9.5+6$

$a_4=15.5$

Let n=5:

$a_5=9.5+2(5-1)$

$a_5=9.5+2(4)$

$a_5=9.5+8$

$a_5=17.5$

Let n=6:

$a_6=9.5+2(6-1)$

$a_6=9.5+2(5)$

$a_6=9.5+10$

$a_6=19.5$

We have confirmed that we get all 6 of the mentioned points using the equation they gave.

5 0

3 years ago