Plan B. to me is he obvious answer.
Answer:
Initial 18 degrees Celsius
After 20 minutes, 5 degrees Celsius
Step-by-step explanation:
It’s initial temperature can be calculated as at the time when x = 0
When x = 0, the temperature is -6+24 = 18 degrees Celsius
This is because the exponent part equals 1 since anything raised in to the power of zero is one.
After twenty minutes,
T(x) = -6 +24e^-0.038(20)
T(x) = -6 + 11.224 = 5.224
And that is approximately 5 degrees Celsius to the nearest degree
Answer:
2.62 seconds
Step-by-step explanation:
Let
t ----> the time in seconds
h(t) ----> he height of the ball, in feet
we have
![h(t)=-16t^2+40t+5](https://tex.z-dn.net/?f=h%28t%29%3D-16t%5E2%2B40t%2B5)
we know that
When the ball hits the ground, the height is equal to zero
so
![-16t^2+40t+5=0](https://tex.z-dn.net/?f=-16t%5E2%2B40t%2B5%3D0)
The formula to solve a quadratic equation of the form
is equal to
in this problem we have
![-16t^2+40t+5=0](https://tex.z-dn.net/?f=-16t%5E2%2B40t%2B5%3D0)
so
substitute in the formula
therefore
The solution is t=2.62 seconds