Answer: x= -9/19
Step-by-step explanation:
5x+18/8=x/4
5x+ 9/4=x/4
5x+9/4-9/4=x/4-9/4
5x= x-9/4
5x(4)=x-9/4(4)
20x=x-9
20x-x=x-9-x
19x=-9
19x/19=-9/19
x=-9/19
Answer:
1/5, 1/6, 1/7, 1/8,1/9, 1/10,1/11,1/12
The answer to your question is -1 < y < 3
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Answer:
roots=(5±sqrt(33))/4
Step-by-step explanation:
roots=(-b±sqrt(b^2-4ac))/2a
roots=(-(-5)±sqrt(25+8))/(2*2)
roots=(5±sqrt(33))/4
roots=(5+sqrt(33))/4 and (5-sqrt(33))/4

To find the gradient of the tangent, we must first differentiate the function.

The gradient at x = 0 is given by evaluating f'(0).

The derivative of the function at this point is negative, which tells us <em>the function is decreasing at that point</em>.
The tangent to the line is a straight line, so we will have a linear equation of the form y = mx + c. We know the gradient, m, is equal to -1, so

Now we need to substitute a point on the tangent into this equation to find c. We know a point when x = 0 lies on here. To find the y-coordinate of this point we need to evaluate f(0).

So the point (0, -1) lies on the tangent. Substituting into the tangent equation: