All categories

3 years ago

Two sides of a triangle are 7 and 11 the length of the third side x is expressed

Mathematics

1 answer:

slava [35]3 years ago

8 0

Answer:

The sum of the lengths of any two sides of a triangle must be greater than the length of the third side. ... No; The sum of the lengths of any two sides of a triangle must be greater than the length of the third side. ANSWER: No; 9.

You might be interested in

What is the approximate length of VU? What is the length of the midsegment parallel to VU?

anastassius [24]

u is at (1,-2)

V is at (-6,-6)

using distance formula it is about 8.06 long

so Answer is C

6 0

3 years ago

ABCD diagonals intersect at E. If m∠BAC=4x+5 and m∠CAD=5x-14, then find m∠CAD.

Travka [436]

Answer: m∠CAD = 81°

Step-by-step explanation: <u>Diagonal</u> is a line that unites opposite sides.

ABCD is a prallelogram. One property of diagonal in a parallelogram is it separates the parallelogram in 2 congruent triangles.

The figure below shows ABCD with its diagonals.

Since diagonal divides a parallelogram in 2 congruent triangles, it means the internal angles are also congruent. So

m∠BAC = m∠CAD

4x + 5 = 5x - 14

x = 19

Then, m∠CAD is

m∠CAD = 5(19) - 14

m∠CAD = 81

The angle m∠CAD is 81°.

7 0

2 years ago

A student answer 86 problems on a test correctly and received a grade of 98% how many problems were on the test if all the probl

adoni [48]

Answer:

87 or 88

Step-by-step explanation:

86 is 98% of 87.755102

So, the number of problems must have been 87 or 88

6 0

2 years ago

Consumer products are required by law to contain at least as much as the amount printed on the package. For example, a bag of po

Troyanec [42]

Answer:

The average bag weight must be used to achieve at least 99 percent of the bags having 10 or more ounces in the bag=9.802

Step-by-step explanation:

We are given that

Standard deviation, $\sigma=0.2$ ounces

We have to find the average bag weight must be used to achieve at least 99 percent of the bags having 10 or more ounces in the bag.

$P(x\geq 10)=0.99$

Assume the bag weight distribution is bell-shaped

Therefore,

$P(\frac{x-\mu}{\sigma}\geq 10)=0.99$

We know that

$z=\frac{x-\mu}{\sigma}$

Using the value of z

Now,

$\frac{10-\mu}{0.2}=0.99$

$10-\mu=0.99\times 0.2$

$\mu=10-0.99\times 0.2$

$\mu=9.802$

Hence, the average bag weight must be used to achieve at least 99 percent of the bags having 10 or more ounces in the bag=9.802

5 0

3 years ago

Substitute 2m + n =0 and m + 2n =3

melamori03 [73]

There are several ways you can solve this problem if you're trying to solve for m and n. You can substitute, or systems of equations. However, I'm going to use substitution:

2m + n = 0 => n = -2m

We can input that in for the other equation:

m + 2n = 3 now becomes: m + 2(-2m) = 3

Now we can solve:

m + 2(−2m) = 3

m + −4m = 3

(m + −4m) = 3 (Combine Like Terms)

−3m=3

m = -1

Now we can input that value in to solve for n:

We said that n = -2m, and m = -1, so n = -2(-1):Answer:

n = 2

Your final answer is m = -1, and n = 2, which can also be written as (m,n) = (-1,2)

----------------------

However, if you were solving for m+n:

You would add the two equations!:

2m + n = 0

m + 2n = 3

----------

3m + 3n = 3

Now, you can take 3 common:

3(m+n) = 3

m + n = 1

Your final answer for what m + n equals 1!

3 0

3 years ago