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2 years ago

The Bishop family celebrated a birthday by dining out at a local restaurant. Their

Mathematics

2 answers:

vlabodo [156]2 years ago

8 0

Answer:

the answer would be $114.99

Whitepunk [10]2 years ago

7 0

17.75 hridizk was the www and what

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How do I solve 2m + n = 2 and 3m - 2n = 3 using substitution?

Leona [35]

$\huge \boxed{\mathbb{QUESTION} \downarrow}$

Solve 2m + n = 2 and 3m - 2n = 3 using substitution.

$\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}$

We can use the substitution method to solve linear equations of this form. Let's solve for m & n.

$\left. \begin{array} { l } { 2 m + n = 2 } \\ { 3 m - 2 n = 3 } \end{array} \right.$

To solve a pair of equations using substitution, first solve one of the equations for one of the variables. Then substitute the result for that variable in the other equation.

$2m+n=2, \: 3m-2n=3$

Choose one of the equations and solve it for m by isolating m on the left-hand side of the equal sign.

$2m+n=2$

Subtract n from both sides of the equation.

$2m=-n+2$

Divide both sides by 2.

$m=\frac{1}{2}\left(-n+2\right) \\$

Multiply 1/2 times -n+2.

$m=-\frac{1}{2}n+1 \\$

Substitute $-\frac{n}{2}+1\\$ for m in the other equation, 3m-2n=3.

$3\left(-\frac{1}{2}n+1\right)-2n=3 \\$

Multiply 3 times $-\frac{n}{2}+1\\$ .

$-\frac{3}{2}n+3-2n=3 \\$

Add $-\frac{3n}{2}\\$ to -2n.

$-\frac{7}{2}n+3=3 \\$

Subtract 3 from both sides of the equation.

$-\frac{7}{2}n=0 \\$

Divide both sides of the equation by $-\frac{7}{2}\\$ , which is the same as multiplying both sides by the reciprocal of the fraction.

$\large \underline{\underline{ \bf \: n=0 }}$

Substitute 0 for n in $m=-\frac{1}{2}n+1\\$ . Because the resulting equation contains only one variable, you can solve for m directly.

$\large \underline{ \underline{\bf \: m=1 }}$

The system is now solved.

$\huge \boxed{ \boxed{ \bf \: m=1, \: n=0 }}$

4 0

2 years ago

What is 48% of 72 time 3 divided by 9

devlian [24]

11.52 72×3=216x48÷100÷9= 11.52

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2 years ago

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A video game sets the points needed to reach the next level based on the function g(x) = 7(3)^(x − 1), where x is the current le

AleksandrR [38]

Good morning.

In level 4, the experience needed is:

$\mathsf{g(4) = 7\cdot3^{4-1}}\\ \\ \mathsf{g(4) = 7\cdot3^3 = 7\cdot27}\\ \\ \mathsf{g(4) = 189}$

In the hardest settings, the multiplier is:

$\mathsf{h(4) = 4\cdot 4}\\ \\ \mathsf{h(4) = 16}$

So, the adjusted experience points are: multiplier . base experience

$\mathsf{E(x) = h(x)g(x)}\\ \\ \mathsf{E(4) = h(4)g(4) = 16\cdot 189}\\ \\ \boxed{\mathsf{E(4) = 3024 \ points}}$

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2 years ago

The selling price of an item is $650. It is marked down by %10, but this sale price is still marked up from the cost of $450.

Hoochie [10]

Answer:

nothing

Step-by-step explanation:

You get nothing because it would make -43256742984

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9. Find (f.g)(a) if f(a) = . and g(a) = 2². Fully simplify your answer.

Aleks04 [339]

D is your answer ....

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2 years ago