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pentagon [3]
3 years ago
15

Is a half bigger then a third ?

Mathematics
2 answers:
Assoli18 [71]3 years ago
7 0


1/2 plus 1/3 is 5/6.

You have to find the common denominator

Marta_Voda [28]3 years ago
5 0
Yes 1/2 is bigger than 1/3


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For what values of the variable, do the following fractions exist: y^2-1/y+y/y-3
ale4655 [162]

Answer:

Remember that the division by zero is not defined, this is the criteria that we will use in this case.

1) \frac{y^2 - 1}{y}  + \frac{y}{y - 3}

So the fractions are defined such that the denominator is never zero.

For the first fraction, the denominator is zero when y = 0

and for the second fraction, the denominator is zero when y = 3

Then the fractions exist for all real values except for y = 0 or y = 3

we can write this as:

R / {0} U { 3}

(the set of all real numbers except the elements 0 and 3)

2) \frac{b + 4}{b^2 + 7}

Let's see the values of b such that the denominator is zero:

b^2 + 7 = 0

b^2 = -7

b = √-7

This is a complex value, assuming that b can only be a real number, there is no value of b such that the denominator is zero, then the fraction is defined for every real number.

The allowed values are R, the set of all real numbers.

3) \frac{a}{a*(a - 1) - 1}

Again, we need to find the value of a such that the denominator is zero.

a*(a - 1) - 1 = a^2 - a - 1

So we need to solve:

a^2 - a - 1 = 0

We can use the Bhaskara's formula, the two values of a are given by:

a = \frac{-(-1) \pm \sqrt{(-1)^2 + 4*1*(-1)}  }{2*1}  = \frac{1 \pm \sqrt{5} }{2}

Then the two values of a that are not allowed are:

a = (1 + √5)/2

a = (1 - √5)/2

Then the allowed values of a are:

R / {(1 + √5)/2} U {(1 - √5)/2}

7 0
3 years ago
How to factorise<br><br><img src="https://tex.z-dn.net/?f=%20%7B8x%7D%5E%7B2%7D%20%20-%20%20xy%20-%20%7B7y%7D%5E%7B2%7D%20" id="
kenny6666 [7]
(8x+7y)(x-y) is the answer.
4 0
4 years ago
Two groups of staff at a store are making flowers to decorate the entrance. If Group A were to do it alone, it would take them 1
Tcecarenko [31]

Answer:

\dfrac{6750}{7}

Step-by-step explanation:

Let x be the number of flowers. If Group A were to make x flowers alone, it would take them 10 hours to complete the task, then they make \dfrac{x}{10} flowers in an hour.  If Group B were to make x flowers alone, it would take them 15 hours to complete the task, then they make \dfrac{x}{15} flowers in an hour.

The groups decided to work together. They can make \dfrac{x}{10}+\dfrac{x}{15}=\dfrac{x}{6} together in an hour and it takes them \dfrac{x}{\frac{x}{6}}=6 hours. Group B took a break for 1 hour and 40 minutes (1\dfrac{2}{3} hour), then Group B works

6-1\dfrac{2}{3}=4\dfrac{1}{3} hours.

Thus,

\dfrac{x}{10}\cdot 6-\dfrac{x}{15}\cdot 4\dfrac{1}{3}=300,\\ \\\dfrac{3x}{5}-\dfrac{13x}{45}=300,\\ \\14x=300\cdot 45=13500,\\ \\x=\dfrac{13500}{14}=\dfrac{6750}{7}.

6 0
3 years ago
Please help as soon as you can
dolphi86 [110]

Answer:

I KNOW I HAD IT BEFORE ITS C

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Diane made $286 for 13 hours of work,
lyudmila [28]

Answer:

8 hours

Step-by-step explanation:

286 divided by 13 is 22

so she's making 22 dollars an hour

22 times x = 176

x = 8

she would need to work 8 hours

4 0
3 years ago
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