For this case we propose a system of equations.
We know that a dime equals 10 cents and a nickel equals 5 cents.
So:
x: Let the variable that represents the number of dimes
y: Let the variable that represents the number of nickels
According to the statement we have:
We multiply the first equation by -0.10:
We have the following equivalent system:
We add the equations:
So, Jeff has 3 nickels
Jeff has 12 dimes.
Answer:
12 dimes and 3 nickels
Answer:
False. Because it is the answer.
Answer 3 ten of numbers between -5/6,5/8
multiply there denominators by any number ...
-5/6×48= -40/48
5/8×48= 30/48
Hence
30/48,31/48,32/48,33/48,34/48,35/48,36/48,37/48,38/48,39/38.
Answer 4
1. x-5=9
X=9+5=14
2. 7= y+2
7-2=y
5=y
Answer 5 X/9=-2
X= -2×9
X= -18
5t= 30
t=30/5
t=6
hope it helps friend
Answer:
14
Step-by-step explanation:
Since we're given the conversion 24 cm for every 3 presents wrapped, we can divide our total amount of tape by this conversion, assuming a constant proportion.
Evren has 112 cm of tape. We can write the following proportion:
, where is the number of presents he can wrap with 112 cm.
Cross-multiplying, we have:
1. -7 + 9= -9 + 7 is false
2. Is 4x - 3 = 19 is open, because this could be a valid equation.
3. 16 = 4x - 4
So, 16+4=4x; 4x=20; x=20/4; x=5..... option C is the correct one.
4. length of the classroom is 2.4 times its width.
given length = 42 in, and since length = 2.4 times width, width = 42/2.4,
hence option A) 17.5 in is correct
5. x - 3 = 10
x = 10+3 =13
Option B is the right one.