Answer: C. 9x+6 yd
Step-by-step explanation:
Given: The length of Jin's house= ![3x+4\ yd](https://tex.z-dn.net/?f=3x%2B4%5C%20yd)
The area of Jin's backyard=![9x^2+15x+4\ yd^2](https://tex.z-dn.net/?f=9x%5E2%2B15x%2B4%5C%20yd%5E2)
By middle splitting method, The area of Jin's backyard=![9x^2+12x+3x+4\ yd^2=(3x+1)(3x+4)\ yds](https://tex.z-dn.net/?f=9x%5E2%2B12x%2B3x%2B4%5C%20yd%5E2%3D%283x%2B1%29%283x%2B4%29%5C%20yds)
To find the width of the backyard, divide the area by the length, we get
Width![=\frac{(3x+1)(3x+4)}{(3x+4)}=3x+1](https://tex.z-dn.net/?f=%3D%5Cfrac%7B%283x%2B1%29%283x%2B4%29%7D%7B%283x%2B4%29%7D%3D3x%2B1)
According to the question, only three sides need to fence
![Fencing=3x+1+3x+1+3x+4=9x+6\ yd](https://tex.z-dn.net/?f=Fencing%3D3x%2B1%2B3x%2B1%2B3x%2B4%3D9x%2B6%5C%20yd)
Area= length × width. 2.2×2.2=4.84
The answer is 7/16 because it’s the highest decimal :)) hope this helps!
6(2y-4)+p
If you distribute you can get
2y-24+p ;)