The given equations are:
1) 2y = -x + 9
⇒ x = 9-2y
2) 3x - 6y = -15
⇒3x = 6y - 15
x = 2y - 5
Equating the values of x, we get:
9 - 2y = 2y - 5
9 + 5 = 4y
14 = 4y
y = 3.5
Using this value of y in equation 1 we get:
x = 9 - 2(3.5) = 2
So, the solution set is (2, 3.5)
Step-by-step explanation:
Answer:
If every line parallel to two lines intersects both regions in line segments of equal length, then the two regions have equal areas. In the case of your problem, every line parallel to the bases of the two parallelograms will intersect them in lines segments, each with a width of ℓ.
Answer:
22x+27
Step-by-step explanation:
Let's simplify step-by-step.
9(2x+3)+4x
Distribute:
=(9)(2x)+(9)(3)+4x
=18x+27+4x
Combine Like Terms:
=18x+27+4x
=(18x+4x)+(27)
=22x+27
-3(x+(3))^2-4 is the answer
