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Aleksandr [31]
2 years ago
8

Please answer as soon as possible. Due by 11:59

Mathematics
2 answers:
Basile [38]2 years ago
8 0
15x+40=-47+27
15x+40=-20
15x=-60
X=-4
andreyandreev [35.5K]2 years ago
5 0
15x+-40-47+27
15x=60
divide both by 15 to get 4
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Find three consecutive integers such that the sum of the 1st and 3rd is 60.
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29,30,31 are the numbers
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3 years ago
Given the graphed function below, which of the following ordered pairs are
Paul [167]

Answer:

B

Step-by-step explanation:

On the inverse, you switch the x and y. So on the function there is point (-2,-11) and on the inverse there is point (-11,-2)

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2 years ago
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2x + 4 = 4x how. to solve it ​
ipn [44]

Answer:

x=2

Step-by-step explanation:

2x+4=4x

-2x     -2x  

4=2x/2x

4/2=x

x=2

8 0
2 years ago
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Find the surface area of x^2+y^2+z^2=9 that lies above the cone z= sqrt(x^@+y^2)
Mashcka [7]
The cone equation gives

z=\sqrt{x^2+y^2}\implies z^2=x^2+y^2

which means that the intersection of the cone and sphere occurs at

x^2+y^2+(x^2+y^2)=9\implies x^2+y^2=\dfrac92

i.e. along the vertical cylinder of radius \dfrac3{\sqrt2} when z=\dfrac3{\sqrt2}.

We can parameterize the spherical cap in spherical coordinates by

\mathbf r(\theta,\varphi)=\langle3\cos\theta\sin\varphi,3\sin\theta\sin\varphi,3\cos\varphi\right\rangle

where 0\le\theta\le2\pi and 0\le\varphi\le\dfrac\pi4, which follows from the fact that the radius of the sphere is 3 and the height at which the sphere and cone intersect is \dfrac3{\sqrt2}. So the angle between the vertical line through the origin and any line through the origin normal to the sphere along the cone's surface is

\varphi=\cos^{-1}\left(\dfrac{\frac3{\sqrt2}}3\right)=\cos^{-1}\left(\dfrac1{\sqrt2}\right)=\dfrac\pi4

Now the surface area of the cap is given by the surface integral,

\displaystyle\iint_{\text{cap}}\mathrm dS=\int_{\theta=0}^{\theta=2\pi}\int_{\varphi=0}^{\varphi=\pi/4}\|\mathbf r_u\times\mathbf r_v\|\,\mathrm dv\,\mathrm du
=\displaystyle\int_{u=0}^{u=2\pi}\int_{\varphi=0}^{\varphi=\pi/4}9\sin v\,\mathrm dv\,\mathrm du
=-18\pi\cos v\bigg|_{v=0}^{v=\pi/4}
=18\pi\left(1-\dfrac1{\sqrt2}\right)
=9(2-\sqrt2)\pi
3 0
2 years ago
sThe number of users on a social networking site was 45 thousand in February when theyofficially went public, and grew to 60 tho
svetoff [14.1K]

Given:

No of users in February is 45,000 and in october its 60,000.

P=45000(\frac{4}{3})^{(\frac{3}{2})^t}

t=2

P=45000(\frac{4}{3})^3P=45000(\frac{64}{27})P=5000(\frac{64}{3})P=106666.6667

Therefore, approximate no of users after 2 years is 106667.

6 0
1 year ago
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