Please help ASAP. The question is down below. Thanks

Mathematics

1 answer:

beks73 [17]3 years ago

6 0

Answer:

Step-by-step explanation:

there is three sections to be fenced using 78 m of fence so it would be letter B.

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In an ellipse, the ratio of the distance between the foci and the length of the major axis is called:

Anni [7]

The ratio of the distance between the foci and the length of the major axis is called eccentricity.

<h3>Definitions of dimensions in ellipses</h3>

Dimensionally speaking, an ellipse is characterized by three variables:

Length of the major semiaxis ( $a$ ).
Length of the minor semiaxis ( $b$ ).
Distance between the foci and the center of the ellipse ( $c$ ).

And there is the following relationship:

$c = \sqrt{a^{2}-b^{2}}$ (1)

Another variable that measure how "similar" is an ellipse to a circle is the eccentricity ( $e$ ), which is defined by the following formula:

$e = \frac{c}{a}$ , $0 \ge c \ge 1$ (2)

The greater the eccentricity, the more similar the ellipse to a circle.

Therefore, the ratio of the distance between the foci and the length of the major axis is called eccentricity. $\blacksquare$

To learn more on ellipses, we kindly invite to check this verified question: brainly.com/question/19507943

3 0

2 years ago

Why are decimals called decimals?

natta225 [31]

Answer:

Step-by-step explanation:

Decimal comes from the Latin word decimus, meaning tenth, from the root word decem, or 10. The decimal system, therefore, has 10 as its base and is sometimes called a base-10 system. Decimal can also specifically refer to a number in the decimal system.

8 0

2 years ago

I need help please help me thanks please

Vitek1552 [10]

so we have a table of values, with x,y coordinates, so let's use any two of those points to get the slope of the table and use the point-slope form to get its equation

$~\hspace{2.7em}\stackrel{\textit{let's use}}{\downarrow }\qquad \stackrel{\textit{and this}}{\downarrow }\\\begin{array}{|lr|r|r|r|r|}\cline{1-6}x&0&1&2&3&4\\y&-1&3&7&11&15\\\cline{1-6}\end{array}\\\\[-0.35em]\rule{34em}{0.25pt}\\\\(\stackrel{x_1}{1}~,~\stackrel{y_1}{3})\qquad(\stackrel{x_2}{4}~,~\stackrel{y_2}{15})$

$\stackrel{slope}{m}\implies\cfrac{\stackrel{rise}{\stackrel{y_2}{15}-\stackrel{y1}{3}}}{\underset{run}{\underset{x_2}{4}-\underset{x_1}{1}}}\implies \cfrac{12}{3}\implies 4\\\\\\% point-slope intercept\begin{array}{|c|ll}\cline{1-1}\textit{point-slope form}\\\cline{1-1}\\y-y_1=m(x-x_1)\\\\\cline{1-1}\end{array}\implies y-\stackrel{y_1}{3}=\stackrel{m}{4}(x-\stackrel{x_1}{1})\\\\\\y-3=4x-4\implies y = 4x-1\implies \blacktriangleright y = 4x+(-1)\blacktriangleleft$