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malfutka [58]
3 years ago
10

Books spontaneously catch on fire in temperatures at or above 451, degree Fahrenheit. Write an inequality that is true only for

temperatures (t)(t)left parenthesis, t, right parenthesis at which books spontaneously catch on fire.
Mathematics
1 answer:
Brilliant_brown [7]3 years ago
3 0
For this case, the first thing you should do is define a variable.
 We have then:
 t: temperature (degree Fahrenheit).
 We write then the inequation that adapts to the problem:
 t> = 451
 Answer:
 
an inequality that is true only for temperatures at which books spontaneously catch on fire is:
 
t> = 451
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A polling organization announces that the proportion of American voters who favor congressional term limits is 64 percent, with
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Answer:

We are 95% confident that the proportion of American voters who favor congressional term limits is 64 percent with a difference of 3% for small sample size.

Step-by-step explanation:

95 % confidence means that we are 95 % confident that the the proportion of American voters who favor congressional term limits is 64 percent.

95 % confidence  means that of all the sample about 95 %  values are within in the given range.

And only 5% sample are not included in the given parameter.

Margin of error is the amount of miscalculation or difference in change of circumstances from the obtained data.

3% margin of error usually occurs when the data size is small.

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So this statement tells us that we are 95% confident that the proportion of American voters who favor congressional term limits is 64 percent with a difference of 3% for small sample size.

Margin of error= z *σ/√n→

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3 0
3 years ago
1⁄2 × 1⁄5 =<br><br> help//.....
skad [1K]

Answer:

1/10

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Solve 5x^2 - 7x + 2 = 0 by completing the square.
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Answer:  The correct option is (c) \dfrac{49}{100}.

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5x^2-7x+2=0~~~~~~~~~~~~~~~~~~~(i)

Also, we are to find the constant added on both sides to form the perfect square trinomial.

We have from equation (i) that

5x^2-7x+2=0\\\\\Rightarrow x^2-\dfrac{7}{5}x+\dfrac{2}{5}=0\\\\\\\Rightarrow x^2-2\times x\times \dfrac{7}{10}+\left(\dfrac{7}{10}\right)^2+\dfrac{2}{5}=\left(\dfrac{7}{10}\right)^2\\\\\\\Rightarrow \left(x-\dfrac{7}{10}\right)^2=\dfrac{49}{100}-\dfrac{2}{5}\\\\\\\Rightarrow  \left(x-\dfrac{7}{10}\right)^2=\dfrac{49-40}{100}\\\\\\\Rightarrow  \left(x-\dfrac{7}{10}\right)^2=\dfrac{9}{100}\\\\\\\Rightarrow x-\dfrac{7}{10}=\pm\dfrac{3}{10}\\\\\\\Rightarrow x=\pm\dfrac{3}{10}+\dfrac{7}{10}.

So,

x=\dfrac{3}{10}+\dfrac{7}{10},~~~~~~~~x=-\dfrac{3}{10}+\dfrac{7}{10}\\\\\\\Rightarrow x=\dfrac{10}{10},~~~~~~~~\Rightarrow x=\dfrac{-3+7}{10}\\\\\\\Rightarrow x=1,~-\dfrac{2}{5}.

Thus, the required solution is x=1,~-\dfrac{2}{5}. and the value of the constant added is \dfrac{49}{100}.

Option (c) is correct.

3 0
3 years ago
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