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IrinaK [193]
4 years ago
5

Simplify the expression: 80 - (4 – 1)^3

Mathematics
1 answer:
Anni [7]4 years ago
4 0
Remember PEMDAS ( Parentheses, Exponents, Multiplication⇔ Division, Addition ⇔ Subtraction),  This is the order you work expressions in.

80 - (4 - 1)³   Subtract 1 from 4
  80 - (3)³     Cube 3 (3 x 3 x 3)
  80 - 27      Subtract
      53
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I need help. Only do number 20.
Pie

Answer:

2z-8y

Step-by-step explanation:

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3 years ago
For a soccer practice, the coach set up four cones, labeled W, X, Y, and Z, to mark the edges of the rectangular field.
zhenek [66]

Answer:

Because there are fewer than 30 (not no more than 30) one of the answer i x+y < 30

Because he needs both small and large another answer is x>0 and not x  0

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Find the product: (50z + 20)(10z + 4) ( 1 ) 12. Find the product: (88a + 80)(8a + 8)
vaieri [72.5K]

Answer:

1. 60z, 36

2. 96a, 88

Step-by-step explanation:

1.

First, find the like terms for z. (60z)

Second, find the like terms for 20, 4, and 12. (36)

2.

Combine the 88a and 8a (96a)

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Step-by-step explanation:

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Write the series using summation notation.<br><br> 4 + 8 + 12 + 16 + 20+ . . . + 80
zhannawk [14.2K]

Answer:

\sum ^{20} _{n \to \11} 4n

Step-by-step explanation:

In order to write the series using the summation notation, first we need to find the nth term of the sequence formed. The sequence generated by the series is an arithmetic sequence as shown;

4, 8, 12, 16, 20...80

The nth term of an arithmetic sequence is expressed as Tn = a +(n-1)d

a is the first term = 4

d is the common difference = 21-8 = 8-4 = 4

n is the number of terms

On substituting, Tn = 4+(n-1)4

Tn = 4+4n-4

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The nth term of the series is 4n.

Since the last term is 80, L = 4n

80 = 4n

n = 80/4

n = 20

This shows that the total number of terms in the sequence is 20

According to the series given 4 + 8 + 12 + 16 + 20+ . . . + 80 , we are to take the sum of the first 20terms of the sequence. Using summation notation;

4 + 8 + 12 + 16 + 20+ . . . + 80  = \sum ^{20} _{n \to \11} 4n

4 0
3 years ago
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