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satela [25.4K]
3 years ago
13

1/29+12/58+12/29=

Mathematics
1 answer:
irakobra [83]3 years ago
5 0
Just find a common denominator and find the smallest number that goes into it, which in this case it is 29, so
1/29+6/29+12/29=19/29
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Alex has a truck. 42% of the miles he drove last month were for work. If Alex drove 588 miles for work, how many miles did he dr
Novosadov [1.4K]

Answer:

Step-by-step explanation:

1.588x42=

2. answer - 588=

3 0
3 years ago
Determine if each table shown below represents a function or not ?
yarga [219]
Neither of them are functions. Functions cannot have two of the same numbers in the x value, and since the first table has two 5s in the x column and the second table has two 7s, neither of them can be functions.

Hope this helps :)
5 0
3 years ago
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Frank started an assignment at 6:26 PM and finished it at 7:44 PM. How long did it take him? Give your answer in minutes.
Svet_ta [14]
7.44-6.26=1.18
1.18 in minutes is 78 minutes bc 1 hour is 60 minutes + 18 minutes is 78
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5 0
2 years ago
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Find the midpoint of the segment with given endpoints k(1.7,-7.9) and l(8.5,-8.2)
zhenek [66]
I think it would be 5.2
6 0
3 years ago
What is the perimeter of the trapezoid with vertices Q(8, 8), R(14, 16), S(20, 16), and T(22, 8)? Round to the nearest hundredth
EleoNora [17]
Check the picture below.

so... you can pretty much see how long RS and QT are, you can just count the units off the grid.

now, let's find QR's length

\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&Q&(~ 8 &,& 8~) 
%  (c,d)
&R&(~ 14 &,& 16~)
\end{array}~~ 
%  distance value
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
QR=\sqrt{(14-8)^2+(16-8)^2}\implies QR=\sqrt{6^2+8^2}
\\\\\\
QR=\sqrt{36+64}\implies QR=\sqrt{100}\implies QR=10

and let's also find the length for ST

\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&S&(~ 20 &,& 16~) 
%  (c,d)
&T&(~ 22 &,& 8~)
\end{array}~ 
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
ST=\sqrt{(22-20)^2+(8-16)^2}\implies ST=\sqrt{2^2+(-8)^2}
\\\\\\
ST=\sqrt{4+64}\implies ST=\sqrt{68}\implies ST=\sqrt{4\cdot 17}
\\\\\\
ST=\sqrt{2^2\cdot 17}\implies ST=2\sqrt{17}

so, add the lengths of all sides, and that's the perimeter of the trapezoid.

8 0
3 years ago
Read 2 more answers
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