Answer: The hook would be 2.2 inches (approximately) above the top of the frame
Step-by-step explanation: Please refer to the picture attached for further details.
The top of the picture frame has been given as 9 inches and a 10 inch ribbon has been attached in order to hang it on a wall. The ribbon at the point of being hung up would be divided into 5 inches on either side (as shown in the picture). The line from the tip/hook down to the frame would divide the length of the frame into two equal lengths, that is 4.5 inches on either side of the hook. This would effectively give us two similar right angled triangles with sides 5 inches, 4.5 inches and a third side yet unknown. That third side is the distance from the hook to the top of the frame. The distance is calculated by using the Pythagoras theorem which states as follows;
AC^2 = AB^2 + BC^2
Where AC is the hypotenuse (longest side) and AB and BC are the other two sides
5^2 = 4.5^2 + BC^2
25 = 20.25 + BC^2
Subtract 20.25 from both sides of the equation
4.75 = BC^2
Add the square root sign to both sides of the equation
2.1794 = BC
Rounded up to the nearest tenth, the distance from the hook to the top of the frame will be 2.2 inches
Answer:6120
Step-by-step explanation:
take the decimal in 6.12 and move it to the right three times and thats how I got the answer
The total angle sum of a triangle is 180°
As such, 180= 78 + 2s +4s
102= 6s
s=17
Answer:
The speed of the jet is 
Step-by-step explanation:
The speed traveled by the jet can be found using the relationship between distance and time. Because the problem gives the values for distance and time, they must be replaced in the equation and in this way the requested speed will be found.
1. Write the general equation for the speed:

2. Replace the values of distance and time on the general equation for the speed and make the mathematical operations:


Therefore the speed of the jet is 