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Goryan [66]
3 years ago
15

Earnings You work for 4 h on Saturday and 8 h on Sunday. You also receive a $50 bonus. You earn $164. How much did you earn per

hour
Mathematics
1 answer:
marshall27 [118]3 years ago
6 0
Hello there,

best way to do this one is set up your story line....

4h + 8h + 50 = 164$...

let's make this easier to look at and combine like terms..

12h + 50 = 164$...

Beautiful!!! Now let's try and get the h alone?...

minus 50 to both sides...

12h = 114$..

now divide both sides by 12...

H= 9.50$/hour

Looks like you made 9.50$ an hour but Hey, at least you got that bonus ;)
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A circular pond is to be surrounded by a gravel path. Use the diagram to find the square feet of gravel needed if we know the po
zzz [600]
Hey, I think an image is needed to answer this question.
5 0
3 years ago
Please help to solve it step by step, (show working) please help me
ANTONII [103]
I'm assuming you only need the first triangle. You didn't specify. If you need it after I answer the first one I'll be happy to help though.

To find the area of a triangle you go b(h)/2=a

6cm(3cm)/2
18/2
Area=9

To find the perimeter you add all of the sides together.

4+4+6=P
4+10=P
14= Perimeter
7 0
3 years ago
Find the six trigonometric function values for angle ∅ where its adjacent side is -9 and its hypotenuse is 41. (Theta is located
arsen [322]
Check the picture below.

\bf \textit{using the pythagorean theorem}
\\\\
c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b
\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
\sqrt{41^2-(-9)^2}=b\implies \sqrt{1681-81}=b\\\\\\ \sqrt{1600}=b\implies 40=b\\\\
-------------------------------

\bf sin(\theta )=\cfrac{\stackrel{opposite}{40}}{\stackrel{hypotenuse}{41}}\qquad~~  cos(\theta )=\cfrac{\stackrel{adjacent}{-9}}{\stackrel{hypotenuse}{41}}\qquad~~  tan(\theta )=\cfrac{\stackrel{opposite}{40}}{\stackrel{adjacent}{-9}}
\\\\\\
csc(\theta )=\cfrac{\stackrel{hypotenuse}{41}}{\stackrel{opposite}{40}}\qquad ~~sec(\theta )=\cfrac{\stackrel{hypotenuse}{41}}{\stackrel{adjacent}{-9}}\qquad ~~cot(\theta )=\cfrac{\stackrel{adjacent}{-9}}{\stackrel{opposite}{40}}

3 0
3 years ago
help me with the Quadratic equation.... x2+ (p - 5) x + 2q = 0 has the roots −3 and 6. Find the value of P and the value of q.​
nirvana33 [79]

Step-by-step explanation:

The quadratic equation is x² + (p - 5)x + 2q = 0.

By Vieta's Formula,

we have SOR = -b/a and POR = c/a.

=> (-3) + (6) = -(p - 5) and (-3)(6) = 2q.

=> 3 = 5 - p and -18 = 2q

Hence, p = 2 and q = -9.

Alternate Method:

We have (x + 3) and (x - 6) as factors of the quadratic equation x² + (p - 5)x + 2q = 0.

=> (x + 3)(x - 6) = x² - 3x - 18.

By Comparing Coefficients,

(p - 5) = -3 and 2q = 18.

Hence p = 2 and q = -9.

8 0
3 years ago
3x < −2x + 7
Hunter-Best [27]
Answer: B

Because...
3x + 2x < -2x + 2x + 7
5x < 7
So you have to do addition BEFORE division.
8 0
3 years ago
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