Question

Identify the zeros of the function f(x) =2x^2 − 2x + 13 using the Quadratic Formula. SHOW WORK PLEASE!! I NEED HELP!!

Answer 1

Answer:

$x=\frac{1+5i} {2}$   and  $x=\frac{1-5i} {2}$

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$f(x)=2x^{2} -2x+13$  

Equate the function to zero

$2x^{2} -2x+13=0$  

so

$a=2\\b=-2\\c=13$

substitute in the formula

$x=\frac{-(-2)\pm\sqrt{-2^{2}-4(2)(13)}} {2(2)}$

$x=\frac{2\pm\sqrt{-100}} {4}$

Remember that

$i=\sqrt{-1}$

so

$x=\frac{2\pm10i} {4}$

Simplify

$x=\frac{1\pm5i} {2}$

therefore

$x=\frac{1+5i} {2}$   and  $x=\frac{1-5i} {2}$