Answer:
The product is:
![\left[\begin{array}{cc}15 & 14\\-1 & 9\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D15%20%26%2014%5C%5C-1%20%26%209%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
For this problem you need to multiply the first row only for the two first column of the others matrix and get the desired result:
![\left[\begin{array}{ccc}1&3&1\\-2&1&0\end{array}\right] \times \left[\begin{array}{cc}2&-2\\3&5\\4&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%263%261%5C%5C-2%261%260%5Cend%7Barray%7D%5Cright%5D%20%5Ctimes%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%26-2%5C%5C3%265%5C%5C4%261%5Cend%7Barray%7D%5Cright%5D)
So the value of the element in the position 
is 15
So the value of the element in the position 
is 14
Then with these two values you can determinate the result matrix.
Answer:
2:10
Step-by-step explanation:
multiply both numbers by the same number(ie. 2,3,4) and the rotio will still be the same
Answer:
Step-by-step explanation:
c
Answer:24
Step-by-step explanation:
Answer:
The equations have the same mathematical form:
S = A + V0 t - 1/2 g t^2
They are both quadratic equations in one variable (t here)
This equation expresses the distance traveled by an object in time t in the vertical direction - it does not necessarily refer to a graph
In the other equation, y can be considered a vertical coordinate equation on a graph and x would be the horizontal coordinate
Note that in one equation 3 terms are necessary to describe the displacement of an object in one direction
In the other 2 terms in the x-direction describe the displacement in the other or y-direction
