3 quarters, and two thirds of a quarter so It's [3 2/3]
Answer:
x=-7, y= -20
Step-by-step explanation:
2x - y =6
x - y = 13
when I subract (x-y =13 ) from (2x-y =6)
2x -y =6
-x +y=-13
______________
x = -7
substitute x=-7 in the second equation
-7 - y =13
-y = 13 +7
-Y = 20
Y=-20
x=-7, y= -20
Hi!
I'm not sure how to slove this, but I do know how to solve it ;D
<h3>We can't know the exact value of y, but we can isolate y on one side. First, multiply by z on both sides. </h3>
x + y = 3 * z
<h3>Now subtract x from both sides.</h3>
x - x + y = 3 * z - x
<u>y = 3 * z - x</u>
<h2>The answer is y = 3 * z - x</h2>
Hope this helps! :)
-Peredhel
OK, so the graph is a parabola, with points x=0,y=0; x=6,y=-9; and x=12,y=0
Because the roots of the equation are 0 and 12, we know the formula is therefore of the form
y = ax(x - 12), for some a
So put in x = 6
-9 = 6a(-6)
9 = 36a
a = 1/4
So the parabola has a curve y = x(x-12) / 4, which can also be written y = 0.25x² - 3x
The gradient of this is dy/dx = 0.5x - 3
The key property of a parabolic dish is that it focuses radio waves travelling parallel to the y axis to a single point. So we should arrive at the same focal point no matter what point we chose to look at. So we can pick any point we like - e.g. the point x = 4, y = -8
Gradient of the parabolic mirror at x = 4 is -1
So the gradient of the normal to the mirror at x = 4 is therefore 1.
Radio waves initially travelling vertically downwards are reflected about the normal - which has a gradient of 1, so they're reflected so that they are travelling horizontally. So they arrive parallel to the y axis, and leave parallel to the x axis.
So the focal point is at y = -8, i.e. 1 metre above the back of the dish.
Answer:
Step-by-step explanation:
To inscribe a circle in a given triangle PQR means to construct a circle in the triangle PQR. The incenter of a triangle is the midpoint in the triangle, which can be located by bisecting the three angles of the triangle individually.
The construction is shown in the attachment.
