Answer: y ≥ (3/5)*x - 3
Step-by-step explanation:
In the graph, we can see that we are above a bold line, that goes through the points (0, -3) and (5, 0)
First, let's find the equation for this line:
y = a*x + b
the value of a is the slope and is equal to:
a = (0 - (-3))/(5 -0) = 3/5
and the value of b is the point where the line intersects the y-axis, in this case, b = -3
then our line is
y = (3/5)*x - 3
As the shaded part is above the line, this equality represents the minimum value that y can take for a given x, and because the line is not a doted line, we know that the equality is valid, so we must use the ≥ symbol.
y ≥ (3/5)*x - 3
Answer:
113.04 sq. in.
Step-by-step explanation:
If the diameter of the circle is 12", then the radius is 6" (half the diameter), and the area "A" is (approximately) 3.14 * 6^2. The calculation is approximate because 3.14 is a rounded value for pi.
Answer:
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Step-by-step explanation:
Determining whether a relation is a function on a graph is relatively easy by using the vertical line test. If a vertical line crosses the relation on the graph only once in all locations, the relation is a function. However, if a vertical line crosses the relation more than once, the relation is not a function.
Answer:
angle DFG = 49 degrees
angle JKL = 41 degrees
Step-by-step explanation:
When angles are complementary with each other, it means that if you add both of the angles up, it adds up to 90 degrees.
In this question, you would have to add up angle DFG and angle JKL and find the x that makes the equation equal to 90 degrees.
angle DFG = x + 5
angle JKL = x - 3
(x + 5) + (x - 3) = 90
2x + 2 = 90
2x = 90 - 2
2x = 88
x = 44
But since we have to find out the angle measures, we have to the "x = 44" with the x's in the DFG and JKL angles.
DFG = (44) + 5 = 49
JKL = (44) - 3 = 41
