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4 years ago

Help ? Pleaseeee (: thanks

Mathematics

1 answer:

Reptile [31]4 years ago

6 0

Slope is -3 and y-intercept is 9

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Write a unit rate for the situation.<br><br> 270 miles in 6 hours<br><br> ___miles per hour

allsm [11]

270/6 = 45 miles per hour

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3 years ago

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What is the slope of a line parallel to the line whose equation is 5x + 3y = 15

kifflom [539]

For two lines to be parallel, they must have the same slope...

3y=-5x+15

y=-5x/3 +5, y=mx+b, where m=slope so:

A parallel line with have a slope of -5/3

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4 years ago

What is the standard form of this circle m(2,4) n(9,4)

Helga [31]

You'd have to find slope so you would use y1-y2 over x2-x1 so itd be 4-4 over 9-2 thatd equal 0/7 thats ur slope. using slope intercept form y=mx+b plug in ur slope y=0/7 x + 4 (y- intecept) then youd subtract the 0/7 x from both so youd have -0/7x+y=4 and that is in standard form.

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3 years ago

Describe the x-values for which (a) f is increasing or decreasing, (b) f(x) > 0 and (c) f(x) < 0

Kryger [21]

(a) The function "f" is increasing for the x-values of [(-∞) < x ≤ 0] and [2 < x < ∞], while "f" is decreasing for the x-values of [0 < x ≤ 2].

(b) The function f(x) is greater than 0 at [(-1) < x < ∞], excluding the point (x = 2)

In the reference attachment attached along with the question statement, we are provided with a graph of a certain function "f",

And as per the question statement, we are required to determine the x-values for the following:

(a) for which "f" is increasing or decreasing,

(b) [f(x) > 0]

From the graph, it is very clear that, the slope is rising from [(-∞) < x ≤ 0] and [2 < x < ∞], while, declining from [0 < x ≤ 2] of the x-axis. Therefore,

(a) The function "f" is increasing for the x-values of [(-∞) < x ≤ 0] and [2 < x < ∞], while "f" is decreasing for the x-values of [0 < x ≤ 2].

(b) The function f(x) is greater than 0 at [(-1) < x < ∞], excluding the point (x = 2)

To learn more about x-values of increasing or decreasing functions, click on the link below.

brainly.com/question/28912753

#SPJ1

7 0

1 year ago

GIVING OUT BRAINLIEST TO WHOEVER GETS ALL OF THEM RIGHT

Thepotemich [5.8K]

Answer:

4) $\frac{x}{7\cdot x +x^{2}}$ is equivalent to $\frac{1}{7+x}$ for all $x \ne -7$ . (Answer: A)

5) $\frac{-14\cdot x^{3}}{x^{3}-5\cdot x^{4}}$ is equivalent to $-\frac{14}{1-5\cdot x}$ for all $x \ne \frac{1}{5}$ . (Answer: B)

6) $\frac{x+7}{x^{2}+4\cdot x - 21}$ is equivalent to $\frac{1}{x-3}$ for all $x \ne 3$ . (Answer: None)

7) $\frac{x^{2}+3\cdot x -4}{x+4}$ is equivalent to $x - 1$ . (Answer: None)

8) $\frac{2}{3\cdot a}\cdot \frac{2}{a^{2}}$ is equivalent to $\frac{4}{3\cdot a^{3}}$ for all $a\ne 0$ . (Answer: A)

Step-by-step explanation:

We proceed to simplify each expression below:

4) $\frac{x}{7\cdot x +x^{2}}$

(i) $\frac{x}{7\cdot x +x^{2}}$ Given

(ii) $\frac{x}{x\cdot (7+x)}$ Distributive property

(iii) $\frac{1}{7+x} \cdot \frac{x}{x}$ Distributive property

(iv) $\frac{1}{7+x}$ Existence of multiplicative inverse/Modulative property/Result

Rational functions are undefined when denominator equals 0. That is:

$7+x = 0$

$x = -7$

Hence, we conclude that $\frac{x}{7\cdot x +x^{2}}$ is equivalent to $\frac{1}{7+x}$ for all $x \ne -7$ . (Answer: A)

5) $\frac{-14\cdot x^{3}}{x^{3}-5\cdot x^{4}}$

(i) $\frac{-14\cdot x^{3}}{x^{3}-5\cdot x^{4}}$ Given

(ii) $\frac{x^{3}\cdot (-14)}{x^{3}\cdot (1-5\cdot x)}$ Distributive property

(iii) $\frac{x^{3}}{x^{3}} \cdot \left(-\frac{14}{1-5\cdot x} \right)$ Distributive property

(iv) $-\frac{14}{1-5\cdot x}$ Commutative property/Existence of multiplicative inverse/Modulative property/Result

Rational functions are undefined when denominator equals 0. That is:

$1-5\cdot x = 0$

$5\cdot x = 1$

$x = \frac{1}{5}$

Hence, we conclude that $\frac{-14\cdot x^{3}}{x^{3}-5\cdot x^{4}}$ is equivalent to $-\frac{14}{1-5\cdot x}$ for all $x \ne \frac{1}{5}$ . (Answer: B)

6) $\frac{x+7}{x^{2}+4\cdot x - 21}$

(i) $\frac{x+7}{x^{2}+4\cdot x - 21}$ Given

(ii) $\frac{x+7}{(x+7)\cdot (x-3)}$ $x^{2} -(r_{1}+r_{2})\cdot x +r_{1}\cdot r_{2} = (x-r_{1})\cdot (x-r_{2})$

(iii) $\frac{1}{x-3}\cdot \frac{x+7}{x+7}$ Commutative and distributive properties.

(iv) $\frac{1}{x-3}$ Existence of multiplicative inverse/Modulative property/Result

Rational functions are undefined when denominator equals 0. That is:

$x-3 = 0$

$x = 3$

Hence, we conclude that $\frac{x+7}{x^{2}+4\cdot x - 21}$ is equivalent to $\frac{1}{x-3}$ for all $x \ne 3$ . (Answer: None)

7) $\frac{x^{2}+3\cdot x -4}{x+4}$

(i) $\frac{x^{2}+3\cdot x -4}{x+4}$ Given

(ii) $\frac{(x+4)\cdot (x-1)}{x+4}$ $x^{2} -(r_{1}+r_{2})\cdot x +r_{1}\cdot r_{2} = (x-r_{1})\cdot (x-r_{2})$

(iii) $(x-1)\cdot \left(\frac{x+4}{x+4} \right)$ Commutative and distributive properties.

(iv) $x - 1$ Existence of additive inverse/Modulative property/Result

Polynomic function are defined for all value of $x$ .

$\frac{x^{2}+3\cdot x -4}{x+4}$ is equivalent to $x - 1$ . (Answer: None)

8) $\frac{2}{3\cdot a}\cdot \frac{2}{a^{2}}$

(i) $\frac{2}{3\cdot a}\cdot \frac{2}{a^{2}}$

(ii) $\frac{4}{3\cdot a^{3}}$ $\frac{a}{b}\cdot \frac{c}{d} = \frac{a\cdot b}{c\cdot d}$ /Result

Rational functions are undefined when denominator equals 0. That is:

$3\cdot a^{3} = 0$

$a = 0$

Hence, $\frac{2}{3\cdot a}\cdot \frac{2}{a^{2}}$ is equivalent to $\frac{4}{3\cdot a^{3}}$ for all $a\ne 0$ . (Answer: A)

6 0

3 years ago