exists and is bounded for all 
. We're told that 
. Consider the interval [0, 3]. The mean value theorem says that there is some 
such that
Since 
, we have
so 19 is the largest possible value.
Answer:
2
Step-by-step explanation:
Simplify 3y=6x+1;
y=2x-1/3
y=mx+b , where m represents the slope.
Slope; 2
I need more info to answer this question
Answer:
Step-by-step explanation:
Amari= Graph C and Solution is (-6,-2)
Bella= Graph A and Solution is (3,4)
Carl= Graph B and Solution is (0,-3)
0 solutions because the slopes are the same. The lines will never cross because they are at the exact same angle.
No, I do not agree with Joey because the lines have different slopes and will lead to the system cross which is the solution.
1st graph: y=2x-1 and y=7 solution #1= (4,7)
2nd graph: y=-2x-3 and y=1/2x solution #2= (-2,1)
3rd graph: y=x and y= -1/5+6 solution #3= (5,5)
I had this exact same assignment a few months ago, my teacher didn't use the 2nd slide but I had the 1st and 3rd slide so this should help!
The solution to the given differential equation is yp=−14xcos(2x)
The characteristic equation for this differential equation is:
P(s)=s2+4
The roots of the characteristic equation are:
s=±2i
Therefore, the homogeneous solution is:
yh=c1sin(2x)+c2cos(2x)
Notice that the forcing function has the same angular frequency as the homogeneous solution. In this case, we have resonance. The particular solution will have the form:
yp=Axsin(2x)+Bxcos(2x)
If you take the second derivative of the equation above for yp , and then substitute that result, y′′p , along with equation for yp above, into the left-hand side of the original differential equation, and then simultaneously solve for the values of A and B that make the left-hand side of the differential equation equal to the forcing function on the right-hand side, sin(2x) , you will find:
A=0
B=−14
Therefore,
yp=−14xcos(2x)
For more information about differential equation, visit
brainly.com/question/18760518
