Write the numbers 3, 2, and 8 in an addition sentence. Show two more ways to find the sum.
2 answers:
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Let <em>X</em> be a random number selected from the interval. Then the probability density for the random variable <em>X</em> is
8 and 10 are the only even integers that fit the given criterion (6 is more than 0.25 away from 6.35), so that we're looking to compute
P(|<em>X</em> - 8| < 0.25) + P(|<em>X</em> - 10| < 0.25)
… = P(7.75 < <em>X</em> < 8.25) + P(9.75 < <em>X</em> < 10.25)
… = P(7.75 < <em>X</em> < 8.25) + P(9.75 < <em>X</em> < 10)
(since P(<em>X</em> > 10) = 0)
… = 0.2740 (8.25 - 7.75) + 0.2740 (10 - 9.75)
… = 0.2055
Answer:
45% probability that a randomly selected customer saw the advertisement on the internet or on television
Step-by-step explanation:
We solve this problem building the Venn's diagram of these probabilities.
I am going to say that:
A is the probability that a customer saw the advertisement on the internet.
B is the probability that a customer saw the advertisement on television.
We have that:
In which a is the probability that a customer saw the advertisement on the internet but not on television and is the probability that the customers saw the advertisement in both the internet and on television.
By the same logic, we have that:
12% saw it on both the internet and on television.
This means that
20% saw it on television
This means that
37% of customers saw the advertisement on the internet
This means that
What is the probability that a randomly selected customer saw the advertisement on the internet or on television
45% probability that a randomly selected customer saw the advertisement on the internet or on television