<h3>
Answer: -3x-3y=-30= x=−y+10 </h3><h3>x+y+10= x=−y+10</h3>
Answer:

Step-by-step explanation:
we would like to solve the following equation for x:

to do so isolate
to right hand side and change its sign which yields:

simplify Substraction:

get rid of only x:

simplify addition of the left hand side:

divide both sides by q+p Which yields:

cross multiplication:

distribute:

isolate -pq to the left hand side and change its sign:

rearrange it to standard form:

now notice we end up with a <u>quadratic</u><u> equation</u> therefore to solve so we can consider <u>factoring</u><u> </u><u>method</u><u> </u><u> </u>to use so
factor out x:

factor out q:

group:

by <em>Zero</em><em> product</em><em> </em><em>property</em> we obtain:

cancel out p from the first equation and q from the second equation which yields:

and we are done!
Answer:
c. Asking people leaving a local election to take part in an exit poll
Step-by-step explanation:
Asking people leaving a local election to take part in an exit poll best represents the highest potential for nonresponse bias in a sampling strategy because of the importance of the local election compared to the exit polls.
It is worthy of note that nonresponse bias occurs when some respondents included in the sample do not respond to the survey. The major difference here is that the error comes from an absence of respondents not the collection of erroneous data. ...
Oftentimes, this form of bias is created by refusals to participate for one reason or another or the inability to reach some respondents.
There are 8000 millimeters because 1 liter is also 1000 millimeters
Answer:
(B) $5.25
Step-by-step explanation:
We can create an equation to represent this problem.
Let's assume
is the cost of a ferris wheel ticket,
is the cost of a snow cone, and
is the cost of a cotton candy.
We bought two ferris wheel tickets, one snow cone, and one cotton candy. After a discount of 6 dollars, the price was 12.75.
This makes the equation 
Since we know the value of each ferris wheel ticket and the snow cone, we can simplify our equation by substituting in these values.

We can now subtract 7.5 from both sides to get the value of
, the cotton candy price.

So the cotton candy cost $5.25.
Hope this helped!