Classify the system of equations. 2x + y - 3 = 0 x + y - 1 = 0
1 answer:
Solve the following system:
{-3 + 2 x + y = 0 | (equation 1)
{-1 + x + y = 0 | (equation 2)
Express the system in standard form:
{2 x + y = 3 | (equation 1)
{x + y = 1 | (equation 2)
Subtract 1/2 × (equation 1) from equation 2:
{2 x + y = 3 | (equation 1)
{0 x+y/2 = (-1)/2 | (equation 2)
Multiply equation 2 by 2:
{2 x + y = 3 | (equation 1)
{0 x+y = -1 | (equation 2)
Subtract equation 2 from equation 1:
{2 x+0 y = 4 | (equation 1)
{0 x+y = -1 | (equation 2)
Divide equation 1 by 2:
{x+0 y = 2 | (equation 1)
{0 x+y = -1 | (equation 2)
Collect results:
Answer: {x =2 , y = -1
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sinB/b = sinA/a
sinB/3 = sin(30°)/2
sinB = (3/2)sin(30°) = 0.75
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