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nlexa [21]
4 years ago
9

Help me find the area of the shaded region

Mathematics
1 answer:
dalvyx [7]4 years ago
7 0
I think it’s 50 but idk
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Find the value of x - this is circle segments.
TEA [102]

Answer:

x = 12

Step-by-step explanation:

Given a tangent and a secant from an external point to the circle, then

The square of the tangent is equal to the product of the external part of the secant and the entire secant, that is

x² = 8(8 + 10) = 8 × 18 = 144 ( take the square root of both sides )

x = \sqrt{144} = 12

7 0
3 years ago
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Solve for x. <br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%7D%7B2%7D%20%20%3D%20%20-%207" id="TexFormula1" title=" \frac{
weeeeeb [17]

Answer:

x = -14

Step-by-step explanation:

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Write down the first even multiple of 7
Fiesta28 [93]

Answer:

14

Step-by-step explanation:

multiples are the list of number that can be multiplied by a certain number.

list the multiples

make a chart

1 × 7 = 7 (odd)

2 × 7 = 14 (even)

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3 years ago
If you earned $60 from $500 in sales , What is the percent commission?
Rom4ik [11]

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300

Step-by-step explanation:

5 0
3 years ago
a group of astronauts launched a model rocket from a platform. Its flight path is modeled by h= -4t^2+24t+13 where h is the heig
Eddi Din [679]

Answer:

6.5 seconds

Step-by-step explanation:

Keep in mind that when h=0, this is the same height for both when the model rocket takes off and lands, so when the rocket lands, time is positive. Thus:

h=-4t^2+24t+13\\\\0=-4t^2+24t+13\\\\t=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\ \\t=\frac{-24\pm\sqrt{24^2-4(-4)(13)}}{2(-4)}\\ \\t=\frac{-24\pm\sqrt{576+208}}{-8}\\\\t=\frac{-24\pm\sqrt{576+208}}{-8}\\\\t=\frac{-24\pm\sqrt{784}}{-8}\\\\t=\frac{-24\pm28}{-8}\\\\t=\frac{-24-28}{-8}\\ \\t=\frac{-52}{-8}\\ \\t=\frac{52}{8}\\\\t=6.5

So, the amount of seconds that the model rocket stayed above the ground since it left the platform is 6.5 seconds

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3 years ago
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