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vovangra [49]
3 years ago
8

what is the volume of a rectangular prism that has a length of 8.5 centimeters (cm), a width of 3.2 centimeters, and a height of

6 centimeters
Mathematics
1 answer:
Yuki888 [10]3 years ago
3 0

Answer:

The volume of the rectangular prism is 163.2cm^3

Step-by-step explanation:

A rectangular prism is in the shape of cuboid which has three dimensions i.e Length, width and height.

Given: Length =8.5 cm width= 3.2 cm  and Height= 6 cm

The volume of a Cuboid = Length*Width*Height

Applying the given dimensions in the formula:

   

          The volume of a Cuboid=  8.5cm*3.2cm*6cm

                                               =  163.2cm^3

The volume of the rectangular prism is 163.2cm^3

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<h3>Answer:</h3>

25

<h3>Step-by-step explanation:</h3>

Let w represent the weight of the animal in pounds, and d the age in days. The problem statement tells us ...

... w = 75 +2d

We want to find d when w > 125.

... 75 +2d > 125 . . . . . substitute the above expression for w

... 2d > 50 . . . . . . . . . subtract 75

... d > 25 . . . . . . . . . . . divide by 2

The animal will weigh more than 125 pounds when it is more than 25 days old.

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What’s the answer for x??
zubka84 [21]

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Step-by-step explanation:

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Consider Akelia’s sequence 5, 8, 11, 14, 17, ….<br> d. Explain Johnny’s formula.
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Solve: <br>x + y = 7<br>3x - 2y = 11<br><br>By using Substituting method.​
Salsk061 [2.6K]

\large\underline{\sf{Solution-}}

\sf  \longmapsto x + y = 7 \: \: - - - (i)

\sf  \longmapsto 3x - 2y = 11 \: \: - - - (ii)

<u>By first equation,</u>

\sf  \longmapsto x + y = 7

\sf  \longmapsto x = 7 - y

<u>Now, we can find the original value of y.</u>

\sf \longmapsto 3x - 2y = 11

\sf  \longmapsto 3(7 - y) - 2y = 11

\sf  \longmapsto 21 - 3y - 2y = 11

\sf  \longmapsto 21 - 5y = 11

\sf  \longmapsto - 5y = 11 - 21

\sf  \longmapsto - 5y =  - 10

\sf  \longmapsto y = \dfrac{ - 10}{ - 5}

\sf  \longmapsto y = 2

<u>Now, we can find the original value of x.</u>

\sf  \longmapsto x + y = 7

\sf  \longmapsto x + 2 = 7

\sf  \longmapsto x = 7 - 2

\sf  \longmapsto x = 5

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