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3 years ago

Find the intersection point for the following liner function f(x)= 2x+3 g(x)=-4x-27

Mathematics

1 answer:

Leona [35]3 years ago

5 0

Answer:

( -5,-7)

Step-by-step explanation:

f(x)= 2x+3 g(x)=-4x-27

Set the two functions equal

2x+3 = -4x-27

Add 4x to each side

2x+3+4x = -4x-27+4x

6x+3 = -27

Subtract 3

6x+3 - 3 = -27-3

6x = -30

Divide each side by 6

6x/6 = -30/6

x =-5

Now we need to find the output

f(-5) = 2(-5) +3 = -10+3 = -7

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If A = 50 degrees, B = 62 degrees, and a = 4, find b.<br><br> Round to the nearest tenth.

Phoenix [80]

<h3>Answer: 4.6</h3>

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Work Shown:

Use the law of sines

b/sin(B) = a/sin(A)

b/sin(62) = 4/sin(50)

b = sin(62)*4/sin(50)

b = 4.61042489526572

b = 4.6

Make sure your calculator is in degree mode.

8 0

3 years ago

Crawling Crayfish!

boyakko [2]

Answer: Crayfish, 25 s

Step-by-step explanation:

Given

The length of race is 60 cm

Flicker gets a 10 cm head-start

Cray fish covers 6 cm in 5 s i.e. its speed is

$\Rightarrow \dfrac{6}{5}=1.2\ cm/s$

Flicker covers 4 cm in 5 s, its speed is

$\Rightarrow \dfrac{4}{5}=0.8\ cm/s$

Time taken by Cray fish to cover the race is

$\Rightarrow t_1=\dfrac{60}{1.2}\\\\\Rightarrow t_1=50\ s$

Time taken by flicker to cover race with 10 cm head start

$\Rightarrow t_2=\dfrac{60-10}{0.8}\\\\\Rightarrow t_2=62.5\ s$

Time taken by crayfish is less. Hence, crayfish wins the race

When they both covers the same distance, they tied momentarily i.e.

$\Rightarrow 1.2t=10+0.8t\\\Rightarrow 0.4t=10\\\\\Rightarrow t=\dfrac{10}{0.4}\\\\\Rightarrow t=25\ s$

After 25 s, they tied the race.

5 0

3 years ago

Explain your answer please.

andriy [413]

Just do length x width x height

7 0

3 years ago

Can anyone help me please? <br> I’ll mark you as a brainliest

Yuki888 [10]

Answer:

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Consider the universal set U and the sets X, Y, Z. U={1,2,3,4,5,6} X={1,4,5} Y={1,2} Z={2,3,5} What is (Z⋃X′)⋂Y?

beks73 [17]

X' = U - X

= {1,2,3,4,5,6} - {1,4,5}

= {2,3,6}

(ZUX') = {2,3,5} U {2,3,6}

= {2,3,5,6}

(Z⋃X′)⋂Y = {2,3,5,6} ⋂ {1,2}

= {2}

3 0

3 years ago