I= sqrt (-1)
If the power is
- even then the value could be -1 or 1
-odd then the value could be -i or i
99 is odd so now is
-i if (99+1)/2 is even or is
i is (99+1)/2 is odd
Now check (99+1)/2= 100/2= 50,
50 is even so
i^99 = -i
Answer:
15.3 dollars
Step-by-step explanation:
13.50 + (.09 x 20 = 1.8)
13.50 + 1.8
Answer:
<span>⇒x=9</span> (positive solution)
Explanation:
<span><span>x2</span>−36=5x</span>
<span>→<span>x2</span>−36−5x=0</span>
Factor the expression:
We get:
<span><span>(x−9)</span><span>(x+4)</span>=0</span>
First solution:
<span>⇒<span>(x−9)</span>=<span>0<span>x+4</span></span></span>
<span>⇒<span>(x−9)</span>=0</span>
<span>⇒x=<span>9</span></span>
Answer:
Part 1) m∠1 =(1/2)[arc SP+arc QR]
Part 2) ![PR^{2} =PS*PT](https://tex.z-dn.net/?f=PR%5E%7B2%7D%20%3DPS%2APT)
Part 3) PQ=PR
Part 4) m∠QPT=(1/2)[arc QT-arc QS]
Step-by-step explanation:
Part 1)
we know that
The measure of the inner angle is the semi-sum of the arcs comprising it and its opposite.
we have
m∠1 -----> is the inner angle
The arcs that comprise it and its opposite are arc SP and arc QR
so
m∠1 =(1/2)[arc SP+arc QR]
Part 2)
we know that
The <u>Intersecting Secant-Tangent Theorem,</u> states that the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.
so
In this problem we have that
![PR^{2} =PS*PT](https://tex.z-dn.net/?f=PR%5E%7B2%7D%20%3DPS%2APT)
Part 3)
we know that
The <u>Tangent-Tangent Theorem</u> states that if from one external point, two tangents are drawn to a circle then they have equal tangent segments
so
In this problem
PQ=PR
Part 4)
we know that
The measurement of the outer angle is the semi-difference of the arcs it encompasses.
In this problem
m∠QPT -----> is the outer angle
The arcs that it encompasses are arc QT and arc QS
therefore
m∠QPT=(1/2)[arc QT-arc QS]
Answer:
![\begin{array}{cccc}&\text{Prefer Pizza}&\text{Do not Prefer Pizza}&\text{Total}\\\text{Prefer Punch}&23&29&52\\\text{Do not Prefer Punch}&66&7&73\\\text{Total}&89&36&125\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bcccc%7D%26%5Ctext%7BPrefer%20Pizza%7D%26%5Ctext%7BDo%20not%20Prefer%20Pizza%7D%26%5Ctext%7BTotal%7D%5C%5C%5Ctext%7BPrefer%20Punch%7D%2623%2629%2652%5C%5C%5Ctext%7BDo%20not%20Prefer%20Punch%7D%2666%267%2673%5C%5C%5Ctext%7BTotal%7D%2689%2636%26125%5Cend%7Barray%7D)
Step-by-step explanation:
There are 125 members.
89 of them preferred pizza and 23 of 89 preferred punch, so 89-23=66 preferred only pizza.
52 members preferred punch, 23 of them preferred both pizza and punch, so 52-23=29 preferred only punch.
Now,
66 members preferred only pizza,
23 members preferred both,
29 members preferred only punch,
125-66-23-29=7 members did not prefer both
The two-way table is
![\begin{array}{cccc}&\text{Prefer Pizza}&\text{Do not Prefer Pizza}&\text{Total}\\\text{Prefer Punch}&23&29&52\\\text{Do not Prefer Punch}&66&7&73\\\text{Total}&89&36&125\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bcccc%7D%26%5Ctext%7BPrefer%20Pizza%7D%26%5Ctext%7BDo%20not%20Prefer%20Pizza%7D%26%5Ctext%7BTotal%7D%5C%5C%5Ctext%7BPrefer%20Punch%7D%2623%2629%2652%5C%5C%5Ctext%7BDo%20not%20Prefer%20Punch%7D%2666%267%2673%5C%5C%5Ctext%7BTotal%7D%2689%2636%26125%5Cend%7Barray%7D)