Step-by-step explanation:
The solution to this problem is very much similar to your previous ones, already answered by Sqdancefan.
Given:
mean, mu = 3550 lbs (hope I read the first five correctly, and it's not a six)
standard deviation, sigma = 870 lbs
weights are normally distributed, and assume large samples.
Probability to be estimated between W1=2800 and W2=4500 lbs.
Solution:
We calculate Z-scores for each of the limits in order to estimate probabilities from tables.
For W1 (lower limit),
Z1=(W1-mu)/sigma = (2800 - 3550)/870 = -.862069
From tables, P(Z<Z1) = 0.194325
For W2 (upper limit):
Z2=(W2-mu)/sigma = (4500-3550)/879 = 1.091954
From tables, P(Z<Z2) = 0.862573
Therefore probability that weight is between W1 and W2 is
P( W1 < W < W2 )
= P(Z1 < Z < Z2)
= P(Z<Z2) - P(Z<Z1)
= 0.862573 - 0.194325
= 0.668248
= 0.67 (to the hundredth)
550×10 I think how do you want it to be explained
answer:
△JKI ≅ △CED
step-by-step explanation:
- like i mentioned before, they look similar and fulfill the SSS triangle theorem (this time's the theorem is different only)
Answer:
Step-by-step explanation:
If you look at the objects thrown as garbage, it's a two- or three-dimensional item that takes up space and also has mass and this is a solid waste.
And the landfill that dumps such garbage is also three-dimensional.
Hence, the volume module, if the object inside is a solid, either would be
As household numbers rise, landfill space increases.
So,
If H represents the number of household keeps, then it will be a sufficient unit for the purpose of Sophia that is
Answer:5/6
Step-by-step explanation:
