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3 years ago

Please help I’m too bad in algebra

Mathematics

1 answer:

Inga [223]3 years ago

3 0

Which one do you need help with???

You might be interested in

I need help with #14 & #15 quickly!

arsen [322]

Answer:

#14 $\frac{3m^{12} n^{10}-m^{8} n^{10}}4\\$ #15 $-448y^{32}x^{5}$

Step-by-step explanation with pictures.

I hope this helps! :D

4 0

3 years ago

The numerical coefficient of -2pqr

VMariaS [17]

Answer: -2

Explanation: The coefficient is the number to the left of the variable.

Another example would be that 10xy has the coefficient 10.

Something like x^2 has coefficient 1 because x^2 = 1x^2.

7 0

3 years ago

X ^ (2) y '' - 7xy '+ 16y = 0, y1 = x ^ 4

AfilCa [17]

Given a solution $y_1(x)=x^4$ , we can attempt to find another via reduction of order of the form $y_2(x)=x^4v(x)$ . This has derivatives

${y_2}'=4x^3v+x^4v'$
${y_2}''=12x^2v+8x^3v'+x^4v''$

Substituting into the ODE yields

$x^2(x^4v''+8x^3v'+12x^2v)-7x(x^4v'+4x^3v)+16x^4v=0$
$x^6v''+(8x^5-7x^5)v'+(12x^4-28x^4+16x^4)v=0$
$x^6v''+x^5v'=0$

Now letting $u(x)=v'(x)$ , so that $u'(x)=v''(x)$ , you end up with the ODE linear in $u$

$x^6u'+x^5u=0$

Assuming $x\neq0$ (which is reasonable, since $x=0$ is a singular point), you can divide through by $x^5$ and end up with

$xu'+u=(xu)'=0$

and integrating both sides with respect to $x$ gives

$xu=C_1\implies u=\dfrac{C_1}x$

Back-substitute to solve for $v$ :

$v'=\dfrac{C_1}x\implies v=C_1\ln|x|+C_2$

and again to solve for $y$ :

$y=x^4v\implies \dfrac y{x^4}=C_1\ln|x|+C_2$
$\implies y=C_1\underbrace{x^4\ln|x|}_{y_2}+C_2\underbrace{x^4}_{y_1}$

Alternatively, you can solve this ODE from scratch by employing the Euler substitution (which works because this equation is of the Cauchy-Euler type), $t=\ln x$ . You'll arrive at the same solution, but it doesn't hurt to know there's more than one way to solve this.

6 0

4 years ago

Brums [2.3K]

By definition we have that the area of a regular octagon is:
A = 4.83L ^ 2
Where, L is the length of the octagon side.
the similarity ratio = the area ratio.
We have then:
similarity ratio = (50) / (18) = 25/9.
the ratio of the perimeters
A1 = 4.83L1 ^ 2
L1 ^ 2 = A1 / 4.83
L2 ^ 2 = A2 / 4.83
L1 ^ 2 / L2 ^ 2 = A1 / A2 = 25/9
L1 / L2 = 5/3
The perimeter is:
P1 = 8L1
P2 = 8L2
P1 / P2 = 8L1 / 8L2 = L1 / L2 = 5/3
answer:
similarity ratio:
25: 9
the ratio of the perimeters:
5: 3

4 0

4 years ago

Read 2 more answers

Draw any two polygons and write their name

mamaluj [8]

Answer:

Draw a square and pentagon

Step-by-step explanation:

they are both polygons

6 0

3 years ago