I’m pretty sure the correct answer the teacher is looking for is B
Step-by-step explanation:
vector AB(3-(-6); 5-7)
vector AB(9;-2)
AB= =
M is the midpoint of AB
we have B(-5;10) and M(1;7)
let A(x;y)
(x-5)/2 = 1 ⇒ x-5 = 2⇒ x = 7
(10=y)/2 = 7⇒ 10+y = 14 ⇒y= 4
so : A(7;4)
the center of the circle is the midponit of the line joining both ends of the diameter
let A(x;y) be the other end
(-2+x)/2 = 2 ⇒ -2+x = 4⇒ x= 6
(5=y) = -1 ⇒ 5+y = -2 ⇒ y= -7
so the coordinates of the other end are (6; -7)
A,B and C are collinear such as AB=BC so b is the midpoint of AC
(-5+1)/2 = y ⇒ y = -4/2 ⇒ y = -2
((-3=x)/2 = 7 ⇒ -3+x = 14 ⇒ x = 17
so x= 17 and y = -2
Answer:
..2.50x + 3.75x = 15..
Step-by-step explanation:
i think
Y = -0.4x
1) It is a straight line
2) I passes through the origin (0,0), because the y-intercpet is 0.
3) The slope is negative, so it passes throuh II and III quadrants
4) The magnitude of the slope = 0.4
4) The angle of the line with the negative side of the x-axis is that whose tan is 0.4 => angle = 21.8 °
With all that information you can identify the graph, given that you didn't include the options.
For a regular polygon with n sides, interior angle
= [(n-2) × 180°]/n
So, interior angle of this regular heptagon shape
= [(7 - 2) × 180°]/7
= (5 × 180°)/7
= 900°/7
= (900/7)°
= 128.571° [approximately]