The chance that both come up red is 2/3.
<u>Step-by-step explanation</u>:
First regular die :
The total outcomes are {1,2,3,4,5,6} = 6
Painted red are odd numbers {1,3,5} = 3
Second regular die :
The total outcomes are {1,2,3,4,5,6} = 6
Painted red are one less than perfect square which is 4-1 is {3} = 1
- Probability (both red) = (red in 1st die / total outcome) + (red in 2nd die / total outcome)
P(both red) = 3/6 + 1/6
⇒ 4/6
⇒ 2/3
Answer:
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Answer:
2x² + x - 1 = 0
a= 2 b= 1 c= -1
x = [ -b +- sqr rt( b^2 -4ac) ] / 2*a
x = -1 +- sqr rt (1 - 4 *2*-1) / 4
x1 = [ -1 + (sqr rt (1 +8)) / 4
x1 = ( -1 + sqr rt (9)) / 4
x1 = (-1 + 3) / 4
x1 = .5
x2 = (-1 -3) / 4
x2 = -4 / 4
x2 = -1
And to check that answer: http://www.1728.org/quadratc.htm
Step-by-step explanation:
The quadratic formula is 
So the solution for k is 16.
Hope that helps!
Answer:
It is not a normal distribution but an uniform distribution
Step-by-step explanation:
A uniform distribution is one in which all values are equally likely within a range, therefore in lottery drawings, any of the numbers are likely to appear, however a normal distribution the values are likely to cluster around the mean, or average. Meaning that numbers far away from the mean won't appear that often, however, in lottery drawings, this normal distribution doesn't happen.
