Answer:
it is right are you able to show the multiple choices
Step-by-step explanation:
<em>✴</em><em>✴</em><em>Hope</em><em> </em><em>this</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em><em>.</em><em>✴</em><em>✳</em><em>⤴</em><em>⤴</em><em>⤴</em>
If there are no duplications among the six numbers, then they sit at
<em>six different points</em> on the number line.
Irrational numbers are on the same number line as rational ones.
The only difference is that if somebody comes along, points at one of them,
and asks you to tell him its EXACT location on the line, you can answer him
with digits and a fraction bar if it's a rational one, but not if it's an irrational one.
For example:
Here are some rational numbers. You can describe any of these EXACTLY
with digits and/or a fraction bar:
-- 2
-- 1/2
-- (any whole number) divided by (any other whole number)
(this is the definition of a rational number)
-- 19
-- (any number you can write with digits) raised to
(any positive whole-number power)
-- 387
-- 4.0001
-- (zero or any integer) plus (zero or any repeating decimal)
-- 13.14159 26535 89792
-- (any whole number) + (any decimal that ends, no matter how long it is)
(this doesn't mean that a never-ending decimal isn't rational; it only
means that a decimal that ends IS rational.
Having an end is <em><u>enough</u></em> to guarantee that a decimal is rational,
but it's not <em><u>necessary</u></em> in order for the decimal to be rational.
There are a huge number of decimals that are rational but never end.
Like the decimal forms of 1/3, 1/6, 1/7, 1/9, 1/11, etc.)
--> the negative of anything on this list
Here are some irrational numbers. Using only digits, fraction bar, and
decimal point, you can describe any of these <em><u>as close</u></em> as anybody wants
to know it, but you can never write EXACTLY what it is:
-- pi
-- square root of √2
-- any multiple of √2
-- any fraction of √2
-- e
-- almost any logarithm
We can use elimination to solve the system:
x+2y=0 Multiply the first equation by negative 2 so we can eliminate
2x+4y=0
-2-4y=0 Add them, -2X+2X= 0, -4Y+4Y= 0
2x+4y=0
0=0
Since 0 is indeed equal to 0 you have INFINITELY MANY SOLUTIONS.
you could also put both equation in slope intercept form and see if the slopes and Y-intercept are the same.
Answer:
My hero academia
Step-by-step explanation:
Black butler,attack on titan
