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3 years ago

3. Which set or sets contain -3? Circle all that apply.

Mathematics

1 answer:

natita [175]3 years ago

7 0

Answer:

rational integers and real please mark as brainliest

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What is the distance between (-6,4) and (-8,6)? Choose 1 answer:

lukranit [14]

Answer:

Step-by-step explanation:

We want to find the distance between (-6, 4) and (-8, 6).

We can use the distance formula given by:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2$

Let (-6, 4) be (x₁, y₁) and let (-8, 6) be (x₂, y₂).

Substitute:

$d=\sqrt{(-8-(-6))^2+(6-4)^2$

Evaluate:

$d=\sqrt{(-2)^2+(2)^2$

Evaluate:

$d=\sqrt{4+4}=\sqrt{8}$

Hence, our answer is D.

6 0

3 years ago

5% of is 36<br> A. 72<br> B. 720<br> C. 7.2<br> D. 72.0

Shtirlitz [24]

Answer:

b. 720

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Help

kobusy [5.1K]

The equation of the line is y - 3 = 5(x - 8) ⇒ c

Step-by-step explanation:

The point-slope form of the linear equation is $y-y_{1}=m(x-x_{1})$ , where:

m is the slope of the line
$(x_{1},y_{1})$ is a point on the line

∵ The line passes through point (8 , 3)

∴ $x_{1}$ = 8 and $y_{1}$ = 3

∵ The slope of the line is 5

∴ m = 5

- Substitute these values in the form of the equation below

∵ $y-y_{1}=m(x-x_{1})$

∴ y - 3 = 5(x - 8)

The equation of the line is y - 3 = 5(x - 8)

Learn more:

You can learn more about the linear equations in brainly.com/question/1284310

#LearnwithBrainly

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3 years ago

Miguel spent 1/8 of his savings on a new video game system. Mila spent 12% of her savings on a DVD, and Manny spent 0.1 of his s

IgorLugansk [536]

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4 0

3 years ago

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Use differentials to estimate the amount of paint needed (in m3) to apply a coat of paint 0.04 cm thick to a hemispherical dome

pogonyaev

The amount of paint is the volume of paint needed.

The amount of paint needed is 0.065312 cubic meters

<h3>How to determine the amount of paint needed</h3>

The volume of a hemisphere is:

$V = \frac 23\pi r^3$

Differentiate the above equation

$V' = 2\pi r^2 r'$

The above equation represents the estimate of the amount of paint needed.

Where:

r represents the radius (r = 52/2 m)
r' represents the thickness (r' = 0.04 cm)

So, we have:

$V' = 2\pi r^2 r'$

$V' = 2 * 3.14 * (52/2\ m)^2 * (0.04cm)$

$V' = 2 * 3.14 * (26\ m)^2 * (0.04cm)$

Express cm as m

$V' = 2 * 3.14 * (26\ m)^2 * (0.0004m)$

$V' = 0.065312 m^3$

Hence, the amount of paint needed is 0.065312 cubic meters