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Novosadov [1.4K]
2 years ago
14

Pleas find the area of the composite figure using the image attatched. Thank you! PLEASE NO WEBSITE LINKS!

Mathematics
1 answer:
Travka [436]2 years ago
7 0

Answer:47(whatever the unit is square)

Step-by-step explanation:

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Nine increased by four times a number
Stells [14]

Answer:

9+4x

Step-by-step explanation:

Is this what you want?

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3 years ago
carlos is building a screen door the height of the door is 1 foot more than twice its width what is the width of the door if it
kenny6666 [7]
I think so answer is 3 because 3×2=6. 6+1=7 feet high
4 0
3 years ago
1.32 rewrite as a simplified fraction
Vedmedyk [2.9K]

Answer:

33/25 should be the answer

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
The cost of 5 gallons of ice cream has a variance of 49 with a mean of 37 dollars during the summer. What is the probability tha
VMariaS [17]

Answer:

0.0119 = 1.19% probability that the sample mean would be less than 35.2 dollars if a sample of 77 5-gallon pails is randomly selected

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation(which is the square root of the variance) \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 37, \sigma = \sqrt{49} = 7, n = 77, s = \frac{7}{\sqrt{77}} = 0.7977

What is the probability that the sample mean would be less than 35.2 dollars if a sample of 77 5-gallon pails is randomly selected?

This is the pvalue of Z when X = 35.2.

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{35.2 - 37}{0.7977}

Z = -2.26

Z = -2.26 has a pvalue of 0.0119

0.0119 = 1.19% probability that the sample mean would be less than 35.2 dollars if a sample of 77 5-gallon pails is randomly selected

3 0
3 years ago
* 2) New Clarendon Park is undergoing renovations to is gardens One garden that was a square is being adjusted so that one side
Irina18 [472]
<span>Reading the solution, please, look on the picture) 
Let the side of the square will be X meters. This means that S1=x^2 </span>meters ^2<span>
One side of </span>new rectangular garden will be 2x meters and another (x-3) meters. So S2=2x(x-3) meters ^2
According to the <span>data:
</span><span>S1*1.25=S2
</span>x^2*1.25=<span>2x(x-3)
</span>1.25*x^2=2x^2-6x
0.75x^2-6x=0
3x^2-24x=0
x^2-8x=0
x(x-8)=0
x=8 or x=0
But x>0!
So x  = 8 meters 

The next question is to find S2.
S2=2x(x-3)=2*8*5=80 meters ^ 2

6 0
3 years ago
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