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ipn [44]
3 years ago
11

Given f(x) = 2x+5 and g(x) = -2x-2, evaluate: f(-2)

Mathematics
1 answer:
k0ka [10]3 years ago
7 0

Answer:

f(-2) = 2(-2) + 5 = 1

Step-by-step explanation:

g(x) has no bearing on your final answer here.  Focus on f(x) = 2x + 5:

f(-2) = 2(-2) + 5 = 1

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Ques no 1 b) help me!!!!! <br> I will give you brainliest plzzz
saul85 [17]

Answer:

-4/5

Step-by-step explanation:

r=x/2

a=2x

ar²=-1/16

x^3=-1/8

x=-1/2

sn=a/1-r

=-4/5

6 0
3 years ago
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8/16 reduced equals what?
Veronika [31]
\frac{8}{16}=\frac{\not8^1}{2\times\not8_1}=\frac{1}{2\times1}=\boxed{\frac{1}{2}}
5 0
3 years ago
What is nine less then the product of a number squared and ten
murzikaleks [220]
A number squared would be x squared (x^2)
The product of x squared and ten is 10x^2
Then subtract nine


10x^2 - 9
6 0
3 years ago
A rectangle has a length 6 more than it's width if the width is decreased by 2 and the length decreased by 4 the resulting has a
Rashid [163]

Answer:

Length of original rectangle: 11 units.

\frac{\text{Area of original rectangle}}{\text{Area of new rectangle}}=\frac{55}{21}

\text{Perimeter of new rectangle}=20

Step-by-step explanation:

Let x represent width of the original rectangle.  

We have been given that a rectangle has a length 6 more than it's width. S the length of the original rectangle would be x+6.

We have been given that when the width is decreased by 2 and the length decreased by 4 the resulting has an area of 21 square units.

The width of new rectangle would be x-2.

The length of new rectangle would be x+6-4=x+2.

The area of new rectangle would be (x+2)(x-2).

Now we will equate area of new rectangle with 21 and solve for x as:

(x+2)(x-2)=21

Applying difference of squares, we will get:

x^2-2^2=21

x^2-4=21

x^2-4+4=21+4

x^2=25

Since width cannot be negative, so we will take positive square root of both sides.

\sqrt{x^2}=\sqrt{25}

x=5

Therefore, the width of original rectangle is 5 units.

Length of the original rectangle would be x+6\Rightarrow x+5=11.

Therefore, the length of original rectangle is 11 units.

\text{Area of original rectangle}=5\times 11

\text{Area of original rectangle}=55    

Therefore, area of the original rectangle is 55 square units.

Now we will find ratio of the original rectangle area to the new rectangle area as:

\frac{\text{Area of original rectangle}}{\text{Area of new rectangle}}=\frac{55}{21}

We know that perimeter of rectangle is two times the sum of length and width.

\text{Perimeter of new rectangle}=2((x+2)+(x-2))

\text{Perimeter of new rectangle}=2((5+2)+(5-2))

\text{Perimeter of new rectangle}=2(7+3)

\text{Perimeter of new rectangle}=2(10)

\text{Perimeter of new rectangle}=20

Therefore, the perimeter of the new rectangle is 20 units.

7 0
3 years ago
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