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vladimir1956 [14]
3 years ago
8

An equation for a line in the xy-plane allows you to find the value of y, given x.

Mathematics
2 answers:
Kobotan [32]3 years ago
6 0

An equation in xy-plane will always have two variable x and y.

So if any one of x or y value is given then we can use that to find other x or y value.

Hence given statement is TRUE.

finlep [7]3 years ago
5 0

An equation for a line in the xy-plane allows you to find the value of y, given x

the statement is true

here we are given with the value of x

so we have here two variables available

now it is a fact that if value of a variable is known in a equation we can easily get the value of other variable

here value of x is given which is a variable so it is evident that for a line in the xy-plane allows us to find the value of y, given x.

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3 years ago
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Vadim26 [7]

Answer:

(7,2)

Step-by-step explanation:

x + y = 9 + 2x - 3y = 8 is really two equations, and you should show this by separating x + y = 9 from 2x - 3y = 8 through the use of a comma, or the word "and," or through writing only one equation per line.

Here you have the system of linear equations

 x +   y =  9

2x - 3y = 8.

Let's solve this system by elimination.  Mult. the 1st eqn by 3, obtaining the system

3x + 3y = 27

2x - 3y =    8

-------------------

5x = 35, so that x = 7.  Subbing 7 for x in x + y = 9, we get 7 + y = 9, indicating that y = 2.

Thus, the solution to this system of equations is (7,2).


6 0
3 years ago
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AleksandrR [38]

Answer:

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4 0
3 years ago
A survey of 90 men found that an average amount spent on St. Patrick's day of $55 with a standard deviation of $18. A similar su
dem82 [27]

Answer:

The value of the test statistic is 4.70.

Step-by-step explanation:

The hypothesis for this test can be defined as follows:

<em>H</em>₀: Men do not spend more than women on St. Patrick's day, i.e. μ₁ = μ₂.

<em>H</em>ₐ: Men spend more than women on St. Patrick's day, i.e. μ₁ > μ₂.

The population standard deviations are not known.

So a <em>t</em>-distribution will be used to perform the test.

The test statistic for the test of difference between mean is:

t=\frac{\bar x_{1}-\bar x_{2}}{\sqrt{\frac{s^{2}_{1}}{n_{1}}+\frac{s^{2}_{2}}{n_{2}}} }

Given:

\bar x_{1}=55\\s_{1}=18\\n_{1}=90\\\bar x_{1}=44\\s_{1}=16\\n_{1}=86

Compute the value of the test statistic as follows:

t=\frac{\bar x_{1}-\bar x_{2}}{\sqrt{\frac{s^{2}_{1}}{n_{1}}+\frac{s^{2}_{2}}{n_{2}}} }=\frac{55-44}{\sqrt{\frac{15^{2}}{90}+\frac{16^{2}}{86} }}=4.70

Thus, the value of the test statistic is 4.70.

7 0
3 years ago
The ages of four groups of 10 workers at a factory are shown, which group has the largest mean absolute deviation?
k0ka [10]

I think group 1 if it is wrong then write is comment box

8 0
3 years ago
Read 2 more answers
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