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4 years ago

Write 5 7/8 as an improper fraction

2 answers:

7 0

Improper fractions are when the numerator is greater than the numerator
the given fraction is a mixed fraction where it has both a whole number and a fraction
$5 \frac{7}{8}$
whole number is 5
fraction is 7/8
when bringing it to an improper fraction we need to convert the whole numbers to fractions as well
denominator is 8. then 5 whole numbers means 5*8 = 40
then the 5 whole numbers as a fraction = $\frac{40}{8}$
then when we add the 2 fractions
$\frac{40}{8} + \frac{7}{8} = \frac{47}{8}$
therefore improper fraction is
$\frac{47}{8}$

Dmitrij [34]4 years ago

5 0

$5\times8=40\\40+7=47\\put~it~over~8\\\frac{47}{8}$

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Answer:

Step-by-step explanation:

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The derivative of y = log x is dy/dx = (ln x) / ln 10.

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Read 2 more answers

Suppose a parabola has vertex (6,5) and also passes through the point (7,7). Write the equation of the parabola in vertex form.

jek_recluse [69]

Answer:

Choice B: $y = 2\, (x - 6)^{2} + 5$ .

Step-by-step explanation:

For a parabola with vertex $(h,\, k)$ , the vertex form equation of that parabola in would be:

$\text{$y = a\, (x - h)^{2} + k$ for some constant $a$}$ .

In this question, the vertex is $(6,\, 5)$ , such that $h = 6$ and $k = 5$ . There would exist a constant $a$ such that the equation of this parabola would be:

$y = a\, (x - 6)^{2} + 5$ .

The next step is to find the value of the constant $a$ .

Given that this parabola includes the point $(7,\, 7)$ , $x = 7$ and $y = 7$ would need to satisfy the equation of this parabola, $y = a\, (x - 6)^{2} + 5$ .