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dimulka [17.4K]
4 years ago
8

What number is halfway between 3000 and 4000

Mathematics
2 answers:
bija089 [108]4 years ago
8 0
\frac{3000+4000}{2}=\frac{7000}{2}\to\boxed{3500}
Rom4ik [11]4 years ago
8 0

For this case, what we should do is calculate the average of 3000 and 4000.

For this, we use the following relationship:

n = \frac{x1+x2}{2}

Substituting values we have:

n = \frac{3000+4000}{2}

Rewriting and simplifying the expression we have:

n = \frac{7000}{2} \\n= 3500

Answer:

A number that is halfway between 3000 and 4000 is:

3500

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pav-90 [236]

Answer:

$169.69

Step-by-step explanation:

for this equation disregard the first # (48)

add all of the amount of square feet from the bathrooms (30.5 + 30.5 + 40.5) which gets you 71

multiply 71 x 2.39 = 169.69

your answer is therefore $169.69

5 0
3 years ago
What is the common difference for the arithmetic sequence?
Anna [14]

Answer:

d. 4

Step-by-step explanation:

the numbers in the sequence keep increasing by a unit of 4.

-5 + 4 = -1

-1 +4 = 3

3 + 4 = 7

8 0
3 years ago
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Jlenok [28]
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4 0
4 years ago
Question 1 (1 point)
ra1l [238]

Answer:

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Step-by-step explanation:

6 0
4 years ago
Find the 4th term if the sequend in which a1 = 2 and a n+1 = -4a n + 2
pshichka [43]
a_n_+_1=-4a_n_+_2

dividing both sides by -4, we get:

a_n_+_2=- \frac{a_n_+_1}{4}

this means, each term is its previous term divided by -4.

now we can construct the sequence as follows:

a_1=2

a_2=- \frac{a_1}{4}= - \frac{2}{4}= -\frac{1}{2}

a_3=- \frac{a_2}{4} =- \frac{ \frac{1}{2} }{4}=- \frac{1}{8}

a_4=- \frac{a_3}{4}=- \frac{ \frac{1}{8} }{4}=- \frac{1}{32}



Answer: the last term is -1/32
3 0
3 years ago
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