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forsale [732]
3 years ago
5

How can you use the backward problem-solving strategy to solve a two-step equation

Mathematics
1 answer:
neonofarm [45]3 years ago
5 0
Let's use the equation 5x - 20 = 10 as an example for this.

To work backwards from this, you would add the same amount to each side.

You want to isolate the 5x so that you can solve for x.

To do that, you would add 20.

But again, you must add and subtract the same amount to both sides.

So it would look a bit like this:

5x - 20 + 20 = 10 + 20

That would simplify to 5x = 30, or in other words, x = 6.

Basically, you isolate the multiple of the variable then divide the answer to the equation from that multiple.

In the example, 5 is the multiple and after isolating it, the answer was 30.

30 ÷ 5 = 6

x = 6

Hope this helps :)
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<h3>Answer:  Rhombus</h3>

======================================================

Reason:

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-------------------------

Let's see if this rhombus is a square or not. We'll need to see if the adjacent sides are perpendicular. For that we'll need the slope.

Let's find the slope of AB.

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B = (x_1,y_1) = (7,6) \text{ and } C = (x_2,y_2)  = (6,2)\\\\m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\m = \frac{2 - 6}{6 - 7}\\\\m = \frac{-4}{-1}\\\\m = 4\\\\

Unfortunately the two slopes of 1/4 and 4 are not negative reciprocals of one another. One slope has to be negative while the other is positive, if we wanted perpendicular lines. Also recall that perpendicular slopes must multiply to -1.

We don't have perpendicular lines, so the interior angles are not 90 degrees each.

Therefore, this figure is not a rectangle and by extension it's not a square either.

The best description for this figure is a <u>rhombus</u>.

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