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castortr0y [4]
2 years ago
6

A total of 712 tickets were sold for the school play. They were either adult tickets or student tickets. There were 62 more stud

ent tickets sold than adult tickets. How many adult tickets were sold?
Mathematics
1 answer:
IgorLugansk [536]2 years ago
3 0

Answer:

325 tickets

Step-by-step explanation:

Total amt. of tickets sold= 712

Adults- x

Students- x+62

712 - 62 = 650 tickets

650÷2= 325

Adults- 325 tickets

Students- 325 + 62= 387

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-104=-8(k+8) <br><br> K = ?<br> Solution please if can?
maksim [4K]

Let's solve this question by step by step.

Layout equation.

−104=−8(k+8)

Step 1: Simplify both sides of the equation.

−104=−8(k+8)

−104=(−8)(k)+(−8)(8)(Distribute)

−104=−8k+−64

−104=−8k−64

Step 2: Flip the equation.

−8k−64=−104

Step 3: Add 64 to both sides.

−8k−64+64=−104+64

−8k=−40

Step 4: Divide both sides by -8.

-8k/-8=-40/-8

The answer for this problem is k=5.

5 0
3 years ago
A random sample of 20 UF students is taken to test UFs claim that 54% of the student population are female.
baherus [9]

You didn't give the multiple choice so no one can help you do make sure to include that next time

8 0
2 years ago
Can you explain how you got the answer as well please?
Vikki [24]

Answer:

A. 35

Step-by-step explanation:

The total amount of movies that the critic rates that we are given is 20. Now they want to figure us to figure it out with 100 movies. 20 times 5 is one hundred. We are supposed to look at the 3 star reviews, which is 7 movies. 7 times 5 is 35. Hope this helps!

5 0
2 years ago
Read 2 more answers
Un agricultor a adus la piață 18 saci cu câte 42 de kg de cartofi și 28 de saci cu câte 36 kg de vinete Ce cantitate de legume a
NikAS [45]

Answer:

the number of vegetables did farmer bring in the market is 1764 vegetables

Step-by-step explanation:

The computation of the number of vegetables did farmer bring in the market is shown below:

= 18 bags × 42 kgs + 28 bags × 36 kgs  

= 756 + 1008

= 1764 vegetables

Hence, the number of vegetables did farmer bring in the market is 1764 vegetables

6 0
3 years ago
given examples of relations that have the following properties 1) relexive in some set A and symmetric but not transitive 2) equ
rodikova [14]

Answer: 1) R = {(a, a), (а,b), (b, a), (b, b), (с, с), (b, с), (с, b)}.

It is clearly not transitive since (a, b) ∈ R and (b, c) ∈ R whilst (a, c) ¢ R. On the other hand, it is reflexive since (x, x) ∈ R for all cases of x: x = a, x = b, and x = c. Likewise, it is symmetric since (а, b) ∈ R and (b, а) ∈ R and (b, с) ∈ R and (c, b) ∈ R.

2) Let S=Z and define R = {(x,y) |x and y have the same parity}

i.e., x and y are either both even or both odd.

The parity relation is an equivalence relation.

a. For any x ∈ Z, x has the same parity as itself, so (x,x) ∈ R.

b. If (x,y) ∈ R, x and y have the same parity, so (y,x) ∈ R.

c. If (x.y) ∈ R, and (y,z) ∈ R, then x and z have the same parity as y, so they have the same parity as each other (if y is odd, both x and z are odd; if y is even, both x and z are even), thus (x,z)∈ R.

3) A reflexive relation is a serial relation but the converse is not true. So, for number 3, a relation that is reflexive but not transitive would also be serial but not transitive, so the relation provided in (1) satisfies this condition.

Step-by-step explanation:

1) By definition,

a) R, a relation in a set X, is reflexive if and only if ∀x∈X, xRx ---> xRx.

That is, x works at the same place of x.

b) R is symmetric if and only if ∀x,y ∈ X, xRy ---> yRx

That is if x works at the same place y, then y works at the same place for x.

c) R is transitive if and only if ∀x,y,z ∈ X, xRy∧yRz ---> xRz

That is, if x works at the same place for y and y works at the same place for z, then x works at the same place for z.

2) An equivalence relation on a set S, is a relation on S which is reflexive, symmetric and transitive.

3) A reflexive relation is a serial relation but the converse is not true. So, for number 3, a relation that is reflexive but not transitive would also be serial and not transitive.

QED!

6 0
3 years ago
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