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castortr0y [4]
2 years ago
6

A total of 712 tickets were sold for the school play. They were either adult tickets or student tickets. There were 62 more stud

ent tickets sold than adult tickets. How many adult tickets were sold?
Mathematics
1 answer:
IgorLugansk [536]2 years ago
3 0

Answer:

325 tickets

Step-by-step explanation:

Total amt. of tickets sold= 712

Adults- x

Students- x+62

712 - 62 = 650 tickets

650÷2= 325

Adults- 325 tickets

Students- 325 + 62= 387

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21 first-graders and 54 other students attended a school assembly. What percentage of the students at the assembly were first-gr
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21+ 54= 76

21/76= 27.6%

5 0
3 years ago
IN A CLASS OF 30 STUDENTS 13 OF THEM ARE BOYS WHAT PERCENTAGE ARE GIRLS?
mestny [16]
Class of students - number of students that are boys = numbers of students that are girls

30 - 13 = 17

To change the number of students that are girls into percentage...

17/1 * 1/100 = 17/100

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5 0
3 years ago
Use the distance formula to determine whether ABCD below is a parallelogram. A(-3,2) B(-3,3) C (5,-3) D (-1.-5)
Pani-rosa [81]

Answer:

ABCD is not a parallelogram

Step-by-step explanation:

Use the distance formula to determine whether ABCD below is a parallelogram. A(-3,2) B(-3,3) C (5,-3) D (-1.-5)

We have to find the length of the sides of the parallelogram using the formula below

= √(x2 - x1)² + (y2 - y1)² when given vertices (x1, y1) and (x2, y2)

For side AB

A(-3,2) B(-3,3)

= √(-3 -(-3))² + (3 -2)²

= √0² + 1²

= √1

= 1 unit

For side BC

B(-3,3) C (5,-3)

= √(5 -(-3))² + (-3 -3)²

= √8² + -6²

= √64 + 36

= √100

= 10 units

For side CD

C (5,-3) D (-1.-5)

= √(-1 - 5)² + (-5 - (-3))²

= √-6² + -2²

= √36 + 4

= √40 units

For sides AD

A(-3,2) D (-1.-5)

= √(-1 - (-3))² + (-5 -2)²

= √(2² + -7²)

= √(4 + 49)

= √53 units

A parallelogram is a quadrilateral with it's opposite sides equal

From the above calculation

Side AB ≠ CD

BC ≠ AD

Therefore, ABCD is not a parallelogram

3 0
3 years ago
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