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Nataliya [291]
3 years ago
5

When "P" Dollars is invested at interest rate "i", compounded annually, for "t" tears, the investment grows to "A" dollars, wher

e A=P(1+i)^t. When Sara enters 11th grade, her grandparents deposit $10,000 in a college savings account. Find the interest rate "i", if the $10,000 grows to $11,193.64 in two years.
Mathematics
1 answer:
ycow [4]3 years ago
4 0
The interest rate is 0.58, or 58 percent.

11,193.64 = 10,000 (1 + i)^2
Divide each side by 10,000.
1.119364 = (1 + i)^2
Take the square root of both sides.
1.058 = 1 + i
Subtract 1
i = 0.58
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<h2>\large\mathfrak{{\pmb{\underline{\red{Given}}{\red{:}}}}}</h2>
  • ∠RSU and ∠USV are complementary angles
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<h2>\large\mathfrak{{\pmb{\underline{\color{red}{To~find}}{\color{red}{:}}}}}</h2>
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<h2>\large\mathfrak{{\pmb{\underline{\orange{Solution}}{\orange{:}}}}}</h2>
  • ∠RSU and ∠USV are complementary angles

\sf\implies{ \angle RSU + \angle USV = 90 \degree }

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\sf\implies{4x+5=90}

\sf\implies{4x=90-5}

\sf\implies{4x=85}

\sf\implies{x={\dfrac{85}{4}}}

\sf\implies{ {\orange{\underline{\boxed{\sf{\pmb{x=21.25}}}}}}}

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Option C is correct.  

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Therefore, option C is correct.

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