I believe that is c if I'm wrong I'm very sorry
Answer:
its 9
Step-by-step explanation:
I have gotten it correct on ED
Answer:
V=5.333cubit unit
Step-by-step explanation:
this problem question, we are required to evaluate the volume of the region bounded by the paraboloid z = f(x, y) = 3x² + y² and the square r: -1≤ x ≤ 1, -1 ≤ y ≤ 1
The question can be interpreted as z = f(x, y) = 3x² + y² and the square r: -1≤ x ≤ 1, -1 ≤ y ≤ 1 and we are told to evaluate the volume of the region bounded by the given paraboloid z
The volume V of integral evaluated along the limits of x and y for the 2-D figure, can be evaluated using the expression below
V = ∫∫ f(x, y) dx dy then we can now substitute and integrate accordingly.
CHECK THE ATTACHMENT BELOW FOR DETAILED EXPLATION:
Answer:
Possible C:
(1 , 1 + 3sqrt(3))
(1 , 1 - 3sqrt(3))
Step-by-step explanation:
AB = 6 units
Midpoint of AB is (1,1)
C would be at x = 1
So, (1,y)
(y-1)² + (1+2)² = 6²
(y-1)² = 36 - 9
(y-1)² = 27
y - 1 = 3sqrt(3)
y - 1 = -3sqrt(3)
y = 1 + 3sqrt(3)
y = 1 - 3sqrt(3)