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Solnce55 [7]
4 years ago
5

At full power, how long would it take for the car to accelerate from 0 to 58.0 mph ? neglect friction and air resistance.

Physics
1 answer:
Advocard [28]4 years ago
3 0

For the given problem, we calculate the required time by using the formula P = W/t. 

P = [(1/2)mv_f^2 – (1/2)mv_i^2]/ t 

The car accelerates from 0 -58 mph, so the power engine will be 

P = (1/2) x m x 58^2 / t = 1682 m / t 

According to the problem, the engine produces full power so the time required can be calculated as  

420.5 m / 1.40 = 1682 m / t 

t = 5.6 seconds

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Why does the vertical component of velocity for a projectile change with time, whereas the horizontal component of velocity does
dlinn [17]

Answer

When a body moves in projectile motion it has two components. One of the components is a horizontal component of the velocity and another is a vertical component.

The velocity along the horizontal component does not change because there is no acceleration long horizontal component.  

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5 0
3 years ago
Please answer these!
solong [7]

6. f = 128.62 s^{-1} , T= 0.0077775 s

7. f  = 2.2 * 10^{4} s^{-1}, T = 4.545 * 10^{-5} s

8. 32.64 s^{-1}

9. 3.29 * 10^{14} s^{-1}

Explanation:

Step 1:

6.

For light and sound v = fλ

where v represents the velocity

f represents the frequency

λ represents the wavelength

λ = 2.69 m

v = 346 m/s

f = v/λ = 346/2.69 = 128.62 s^{-1}

Time period is the reciprocal of frequency

T = 1/128.62 = 0.0077775 s

Step 2:

7.

λ = 110 cm = 1.1 m

v = 2.42*10^{4} m/s

f = 2.42*10^{4}/1.1 = 2.2 * 10^{4} s^{-1}

T = 1/(2.2*10^{4}) = 4.545 * 10^{-5} s

Step 3:

8.

λ = 10.6 m

v = 346 m/s

f = v/λ = 346/10.6 = 32.64 s^{-1}

Step 4:

9.

λ = 5.89 * 10^{-7} m

v = 1.94 * 10^{8} m/s

f = v/λ = 3.29 * 10^{14} s^{-1}

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Mazyrski [523]

Answer:

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