Answer:
The speed of the stone is
v = 7.45 m/s
Explanation:
Length, L=0.551m
maximum tension in the spring = 9.6%
So let speed of stone be
Tv = TH + 9.6/ 100 * TH
Tv - m*g = m*v^2/L
TH = m*v^2 / L
Factor mass to cancel in the equation
Solve to v
v^2= L*g*100 / 9.6
Replacing numeric:
v^2=0.551m*9.8m/s^2*100 / 9.6
v = sqrt( 56.24 m^2/s^2)
v = 7.45 m/s
Explanation:
The horizontal velocity reached by the mass is:
v = v₀ + at
vₓ = 0 + (F/m) (1 s − 0 s)
vₓ = F/m
The force is then removed, so the mass continues at this horizontal velocity.
The vertical velocity reached by the mass is:
v = v₀ + at
vᵧ = 0 + (F/m) (2 s − 1 s)
vᵧ = F/m
The force is then removed, so the mass continues at this vertical velocity.
So at 2 seconds, the mass's velocity has equal components in the x and y directions, and continues to have that velocity at 3 seconds.
Since the spacecraft is two earth radii the surface of the earth, it is three earth radii above the center.
Given: Radius of the earth re = 6.38 x 10⁶ m r = 1.91 x 10⁷ m
Mass of the spacecraft Ms = 1600 Kg
Mass of the earth Me = 5.98 x 10²⁴ Kg
G = 6.67 X 10⁻¹¹ N.m²/Kg²
Formula: F = GMeMs/r²
F = (6.67 X 10⁻¹¹ N.m²/Kg²)(5.98 x 10²⁴ Kg)(1,600 Kg)/(1.91 x 10⁷ m)²
F = 6.38 X 10¹⁷ N/3.65 X 10¹⁴ m²
F = 1,748.5 N
The acceleration of gravity on the surface of the Moon is about 1.62 m/s^2.
Explanation:
Black holes are the most massive and dense objects in the whole universe. They are peculiar objects. The gravity near black hole is so strong that even light can not escape it. That is why the name: Black hole. It is formed after the death of a supermassive star. All the mass of the star is condensed in to a very small area having a very string gravity. Imagine the Sun squeezed in to an object of diameter of just 3 km!
You can define it as a dead super massive star from which nothing can escape.
