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Alex73 [517]
3 years ago
6

4/12 of a cake was left over if another 3/12 of the cake is eaten

Mathematics
1 answer:
inn [45]3 years ago
3 0
There would be 1/12 of the cake left. 
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Would you solve the equation 0.25x + 7 = 1/3x – 8 <br> using fractions or decimals? Explain please.
mamaluj [8]

Answer:

x = 180

Step-by-step explanation:

Solve the value of x :

0.25x + 7 = \frac{1}{3}x - 8

-Combine \frac{1}{3}x and 0.25x by subtracting 0.25x by \frac{1}{3}x :

0.25x - \frac{1}{3}x  + 7 = \frac{1}{3}x - \frac{1}{3}x  - 8

-\frac{1}{12}x + 7 = -8

-Subtract 7 on both sides:

-\frac{1}{12}x + 7 - 7 = -8 - 7

-\frac{1}{12}x = -15

-Multiply both sides by -12, the reciprocal of -\frac{1}{12} :

\frac{-\frac{1}{12}x}{-\frac{1}{12}} = \frac{-15}{-\frac{1}{12}}

x = -15 (-12)

x = 180

Therefore, the value of x is 180.

7 0
3 years ago
Find the equuvalent fraction for each number 4/5
stepan [7]
8/10, because it's double the numbers
8 0
3 years ago
When the same probability is assigned to each outcome of a sample space, the experiment is said to have _______ ________ outcome
zhuklara [117]

Answer:

Equally likely

Step-by-step explanation:

Hope this is right!

8 0
2 years ago
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Given y=x^2 how would the graph of y=x^2+4 differ?
satela [25.4K]
A) The graph will move up by 4 units
6 0
3 years ago
The Friendly Sausage Factory (FSF) can produce hot dogs at a rate of 5,750 per day. FSF supplies hot dogs to local restaurants a
NARA [144]

Answer:

A) 22812 hotdogs per run

B) 75 runs/yr

C) 4 days in a run

Step-by-step explanation:

We are given;

Production rate;p = 5750 per day

Steady Usage rate;u = 270 per day

Setup cost of hotdog;S = $67

Annual carrying cost (H) = 47 cents = $0.47 per hot dog

No. of Production days; d = 297 days

A) Let's first find the annual demand given by the formula;

Annual demand;D = pd

D = 5750 × 297

D = 1707750 hot dogs/yr

Now, formula for optimal run size is given by;

Q_o = √[(2DS/H) × (p/(p - u))]

Plugging in the relevant values gives;

Q_o = √[(2 × 1707750 × 67/0.47) × (5750/(5650 - 270))]

Q_o =√520375454.7971209

Q_o = 22812 hotdogs per run

B) formula for Number of runs per year is given as;

No. of Runs = D/Q₀

Thus;

no. of runs = 1707750/22812

no. of runs ≈ 75 runs/yr

C) Length of a run is given by the formula;

Length = Q₀/p

Length = 22812/5750

Length ≈ 4 days in a run

6 0
2 years ago
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