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sdas [7]
3 years ago
13

Hi I need help on #40 please

Mathematics
1 answer:
LekaFEV [45]3 years ago
7 0
The answer is attached

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Required<br> What is the solution for the system below:<br> y = x + 1 and y = x + 1
Dmitry_Shevchenko [17]

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Step-by-step explanation:

3 0
3 years ago
HELP ASAP PLS 20 POINTS WILL GIVE BRAINLIEST
Brrunno [24]

Answer:

The parent function is y = x³.

After a vertical stretch by a factor of 3, obtain

y = 3x³

After a horizontal shift 4 unit to the right, obtain

y = 3(x - 4)³

After a vertical shift 3 units down, obtain

y = 3(x - 4)³ - 3

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6 0
3 years ago
Two airplanes left the same airport and arrived at the same destination at the same time. The first airplane left at 8:00 a.m. a
ddd [48]

The formula for distance is equal to:

d = v * t

where d is distance, v is velocity or speed, and t is time

 

Since the distance travelled by the two airplane is similar, therefore we can create the initial equation:

 

v1 * t1 = v2 * t2

 

We know that v1 = 496, and v2 = 558 so:

 

496 t1 = 558 t2

or

x = 558 t2 / 496

 

We also know that airplane 1 travelled 30 minutes (0.5 hours) earlier than airplane 2, therefore:

 

x = t2 + 0.5

 

Hence,

496 (t2 + 0.5) = 558 t2

496 t2 + 248 = 558 t2

t2 = 4 hours

 

x = t2 + 0.5 = 4 + 0.5

x = 4.5 hours

 

 

So the equation is:

x = 558 t2 / 496

 

And the first plane travelled:

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