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Elena-2011 [213]

3 years ago

14

A rectangle has two pairs of sides of equal length. explain how you can find the unknown length of two side when the length of o

ne side is 4 units, and Perimeter is 14 units.

1 answer:

Minchanka [31]3 years ago

3 0

Simple let's think the missing length is l

l =<span>P
</span> _ ﹣<span>w L = 3 Check = 2 ( l + b) = 2 ( 3 +4 ) = 2 x 7 = 14</span><span>
2 Hope you make me brainliest

</span>

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How is 721 expanded form written

lina2011 [118]

700+20+1 i'm not too sure but i hope this helps

5 0

3 years ago

Read 2 more answers

Imagine the average time to complete a 4-year bachelor degree is actually 4.7 years, based on national data. You collect data on

rusak2 [61]

Answer:

-0.67

Step-by-step explanation:

Given that :

Population mean, μ = 4.7

Sample size, n = 68

Sample mean, M = 4.3

Sample standard deviation, s = 0.6

The effect size, d can be obtained using the relation :

d = (M - μ) / s

d = (4.3 - 4.7) / 0.6

d = - 0.4 / 0.6

d = - 0.66666

d = - 0.67

Hence, effect size associated with a single-sample t test is - 0.67

8 0

3 years ago

If you order these 3 from Least I will give 20 points and mark as brilliant 1.)6 3/5, 7 3/4,6.55,6,7.09 2.) 3 8/20,-3.3,3.41,3.2

natulia [17]

Answer:

1.) 6, 6.55, 6 3/5, 7.09, 7 3/4

2.) -3.3, -3 3/12, 3.27, 3 8/20, 3.41

3.) -0.4, 1/25, 4/50, 12/100, 0.8

Explanation:

1.) 6 3/5, 7 3/4, 6.55, 6, 7.09

6 3/5 -> 6.6

7 3/4 -> 7. 75

Therefore: 6, 6.55, 6 3/5, 7.09, 7 3/4

2.) 3 8/20, -3.3, 3.41, 3.27, -3 3/12

3 8/20 -> 3.04

-3 3/12 -> -3.25

Therefore: -3.3, -3 3/12, 3.27, 3 8/20, 3.41

3.) 4/50, 0.8, 12/100, -0.4, 1/25

4/50 -> 0.08

12/100 -> 0.12

1/25 -> 0.04

Therefore: -0.4, 1/25, 4/50, 12/100, 0.8

4 0

3 years ago

Help solve this math problem please

quester [9]

Answer:

$=536870912$

Step-by-step explanation:

$\frac{\left(2^3\right)^{10}\cdot \:2^{-8}}{2^{-7}}\\\mathrm{Cancel\:}\frac{\left(2^3\right)^{10}\cdot \:2^{-8}}{2^{-7}}:\quad \frac{\left(2^3\right)^{10}}{2}\\\frac{\left(2^3\right)^{10}\cdot \:2^{-8}}{2^{-7}}\\\mathrm{Apply\:exponent\:rule}:\quad \frac{x^a}{x^b}=\frac{1}{x^{b-a}}\\\frac{2^{-8}}{2^{-7}}=\frac{1}{2^{-7-\left(-8\right)}}\\=\frac{\left(2^3\right)^{10}}{2^{-7-\left(-8\right)}}\\\mathrm{Subtract\:the\:numbers:}\:-7-\left(-8\right)=\\=\frac{\left(2^3\right)^{10}}{2}$

$\mathrm{Simplify\:}\left(2^3\right)^{10}:\quad 2^{30}\\\left(2^3\right)^{10}\\\mathrm{Apply\:exponent\:rule}:\quad \left(a^b\right)^c=a^{bc}\\=2^{3\cdot \:10}\\\mathrm{Multiply\:the\:numbers:}\:3\cdot \:10=30\\=2^{30}\\=\frac{2^{30}}{2}\\\mathrm{Cancel\:the\:common\:factor:}\:2\\=2^{29}\\2^{29}=536870912\\=536870912$

7 0

4 years ago

Finding Inverses<br> Find an equation for the inve<br> 3.<br> y = 3x + 2

Kipish [7]

First we swap our x and y variable, so we get

x = 3y + 2

Then, we solve for y
We can first subtract 2 on both sides

x - 2 = 3y

Then we can divide by 3 on both sides to get

x/3 - 2/3 = y

So our final equation is

y = x/3 - 2/3

7 0

3 years ago