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zalisa [80]
3 years ago
12

What is 16 divided by 133.2? show your work

Mathematics
2 answers:
RSB [31]3 years ago
6 0

Answer:

0.12012012012....

Step-by-step explanation:

16/133.2

just do long divison on your paper

= 0.12012012012....

solmaris [256]3 years ago
4 0

Answer: 0.12012012012

Step-by-step explanation:

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Danny has 48 baseball cards in his collection. He would like to give 3/4 of them to his little brother. How many should he give
MAXImum [283]

It would be: 48 * 3/4 = 36

your answer is 36

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2 years ago
What is the solution of the proportion? 14/12 = D/48<br> a. 56<br> b. 672<br> c. 168<br> d. 576
Verdich [7]
So basically we can simplify the fraction by finding the gcf which is the greatest common factor so 14/12 both have 2 in common we simplify that by dividing by 2 so 14÷2 is 7/6 is the fraction on the left hand side and d/48 is the fraction on the right hand side so to solve for d we have to divide 336/6 whixh equals 56 as tour answer. Hoped this helped!!
8 0
3 years ago
Read 2 more answers
Help please explain.
Lubov Fominskaja [6]
25 + 100i is correct because -5 squared is 25 and the the square root of -100 is 100i or 10i in its simplest form.
4 0
3 years ago
Shea wants to wrap a package that is 8 inches by 11 inches by 2 inches. Shea purchased a roll of wrapping paper that is 1 foot w
nekit [7.7K]
First we need to know the surface area of the package:
2(lw) + 2(lh) + 2(wh)
2(8*11) + 2(11*2) + 2(8*2)
2(88) + 2(22) + 2(16)
176 + 44 + 32
252 square inches needed

Wrapping paper is in feet, so convert it to inches before finding the area.
1' = 12"; 2' = 24"
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So, yes there is enough paper to cover all sides of the gift if there are no overlaps.
6 0
3 years ago
Billy is monitoring the exponential decay of a radioactive compound. He has a sample of the compound in a test tube in his lab.
Over [174]

Solution:

Formula for radioactive Decay is given by

R_{0}= R(1-\frac{S}{100})^t

R_{0}= Initial Population

R = Remaining population after time in hours

Rate of Decay = S % per hour

Initial Population = 72 grams

Final population = 15 grams

Rate of Decay = 35 % per hour

Substituting the values to get value of t in hours

72=15(1-\frac{35}{100})^t\\\\ 4.8= (0.65)^t\\\\ t= -3.64→→1 St expression

But taking positive value of t , that is after 3.64 hours the sample of 72 grams decays to 15 grams at the rate of 35 % per hour.

Now , it is also given that, Once the sample reaches a mass of 15 grams, Billy will continually add more of the compound to keep the sample size at a minimum of 15 grams.

Substituting these in Decay Formula

Final Sample = 15 gm

Starting Sample = 15 +k, where k is amount of sample added each time to keep the final sample to 15 grams.

Time is over 3.64 hours i.e new time = 3.64 + t

Rate will remain same i.e 35 % per hour.

15=(15+k)(1-\frac{35}{100})^{3.64+t}→→→  Final expression (Second) , that is inequalities can be used to determine the possible mass of the radioactive sample over time.







5 0
3 years ago
Read 2 more answers
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